You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
The dimensions are Width of the rectangle = 7.2 cm
Length of the rectangle = 4x + 9.7
= 28.8 + 9.7
= 38.5 cm. thats all
The answer is 3 and 3.16227766017
A) Plane because it is a flat surface that extends in two dimensions but exists in a three-dimensional space, and also it isn't a point, a line, or an angle because a line is infinitely thin, a point is infinitesimally small, and an angle is a measurement, not a surface.
Answer:
Step-by-step explanation:
1. T
2. F
3. F
4. T
5. F
6. T
