All three sides always add up to 360 so add the given measures and subtract it from 360 and that would give you your answer.
Answer: There is sufficient evidence to conclude that the proportion of agenda-less meetings is greater than 45%.
Step-by-step explanation:
Given: 
The p-value for this hypothesis test is 0.025.
The level of significance is α=0.05
As p-value< α ∵0.025< 0.05
[if p-value< α , we reject
]
then, we reject the null hypothesis.
i.e. We have sufficient evidence to support the alternative hypothesis.
Hence, the correct statement is : There is sufficient evidence to conclude that the proportion of agenda-less meetings is greater than 45%.
The LCM of 6 and 15 is 30:)
Answer in decimal form: 37.69911184
Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735