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Mumz [18]
2 years ago
15

What is the slope of the line through (-7, -8) and (0,4)

Mathematics
1 answer:
umka21 [38]2 years ago
3 0
The slope is, 12/7 just subtract 4-(-8)/0-(-7)
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Ummm can u plz tell me what u put in these boxes and um answer 4 pls ​
Lorico [155]

Well your answer for problem 4 is 28. IM not sure what the boxes are for though...

7 0
3 years ago
Which of the following polygons has five lines of symmetry?
Ivan
Pentagons are and example.
6 0
3 years ago
Need help with this math
Rudiy27

10,171.07 pesos

To every US dollar, it equal 18.84 pesos.

7 0
3 years ago
Hi, I am new to this website :) I'm currently taking an online trig class on De Moivre's theorem and I don't understand it at al
Vladimir [108]
De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.

For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes

[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))] 

it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.

For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)

[2^6(cos(40*6))+isin(40*6)],

[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)

And the answer is -32 -32 √3 i

Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i

7 0
3 years ago
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.8 parts
Alexxandr [17]

Answer:

The value of the test statistic is t = 2.67

Step-by-step explanation:

The null hypothesis is:

H_{0} = 7.8

The alternate hypotesis is:

H_{1} \neq 7.8

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

In this problem, we have that:

X = 8.2, \mu = 7.8, \sigma = 0.6, n = 16

Then

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{8.2 - 7.8}{\frac{0.6}{\sqrt{16}}}

t = 2.67

The value of the test statistic is t = 2.67

5 0
3 years ago
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