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2 years ago

How do you solve: g(x) = x - 2 ( I think the answer is 2 but how?!)

Mathematics

2 answers:

babymother [125]2 years ago

6 0

Answer:

x-2 =0

x=2

Step-by-step explanation:

we take -2 to the anther side it becomes 2

Paul [167]2 years ago

6 0

Answer:

-2

Step-by-step explanation:

A function is a rule for working out the values y for the given values x

For example, h = 3x and y = x^2 are functions. The notation g(x) is read as g of x. g is the function. g(x) = 3x means the function of x is 3x

So, when solving to find the value of x, you must substitute x for any given value.

For example, f(x) = 10/x. Work out f(5), you must substitute the 5 into the denominatior of the fraction 10/x . This becomes 10/5, which equals to 2.

But for your question, to find the value of x, substitute x with 0

You end up with -2

Hope this helps

BtW. the above statements are just notes. i thought they might help.

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Please answer asap will give the highest points possible

natali 33 [55]

Let cheese wafers = x
chocolate wafers = y

we know they bought 20 total packets so x+y = 20, this can be re-written as x = 20-y

cheese wafers cost 2, so we have 2x
chocolate wafers cost 1, so we have 1y, which is just the letter y

so we know 2x + y = $25

replace x with x=20-y to get:

2(20-y)+y = 25

distribute the parenthesis:

40-2y +y = 25

combine like to terms to get:
40-y = 25

subtract 40 from each side"
-y = -15

divide both sides by -1
y = 15

chocolate wafers was y so they bought 15 chocolate wafers
cheese wafers was x, so they bought 20-15 = 5 cheese wafers

using the substitution method was the easiest way to isolate one of the variables in order to find the solution.

6 0

2 years ago

Read 2 more answers

A farmer from Whidbey Island: A man claims his whalebone can detect water. You design an experiment using a set of 4 cans, 3 emp

tatyana61 [14]

Answer:

The value is $E(x) = 1.25$

Step-by-step explanation:

From the question we are told that

The number of cans is n = 4

The number of can that are empty is N = 3

The number of can filled with water is k = 1

The number number of sets of cans is w = 5

Generally probability of detecting the correct can is mathematically represented as

$p = \frac{k}{n}$

=> $p = \frac{1}{4}$

=> $p = 0.25$

Generally probability of not detecting the correct can is mathematically represented as

$q = 1- p$

$q = 1- 0.25$

$q = 0.75$

Generally the number of cans expected of the farmer to correctly identify by chance is mathematically represented as

$E(x) = w * p$

=> $E(x) = 5 * 0.75$

=> $E(x) = 1.25$

5 0

2 years ago

A number plus 1/3 of the number can be expressed as:

nirvana33 [79]

Answer:

n+n/3

Step-by-step explanation:

n+1/3 n=n+n/3=4n/3

Please mark as Brainliest! :)

Have a nice day.

6 0

3 years ago

A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an

Firlakuza [10]

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

Predicted value

Active value Fraudulent Non-fraudulent

Fraudlent 30 58

non-fraudulent 32 920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of $\left( {b + c} \right)(b+c)$ and the total number of records.

The classification matrix is, shown above

The total number of records is, $30 + 58 + 32 + 920 = 1,040$

The error rate is,

$\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}$

The percentage is $0.0865 \times 100 = 8.65$

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and $\left( {a + b} \right)(a+b)$ .