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valkas [14]
3 years ago
15

HOW TO SOLVE 2/5x=-25

Mathematics
2 answers:
Katena32 [7]3 years ago
8 0

Answer:

2/5x=25

So what you do is because you want to get x by itself you wanna divide the fraction (2/5) over itself and then divide 25/(2/5) which will equal x.

X=25/(2/5)

then you plug in 25/(2/5) and it equals 62.5

or 62 1/2

So

X=62.5

Pepsi [2]3 years ago
6 0

Answer:

x = - \frac{125}{2} = - 62.5

Step-by-step explanation:

Given

\frac{2}{5} x = - 25

Multiply both sides by 5 to clear the fraction

2x = - 125 ( divide both sides by 2 )

x = - \frac{125}{2} = - 62.5

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Simplify: cos2x-cos4 all over sin2x + sin 4x
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Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

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