32°+81°=113°
For a complete triangle to form it needs to be 180°. So all you do is subtract 180° by the sum of 32° and 81°.
180°-113°=67°
The answer is 67°
If the parallel sides are the same length, then the figure must be a parallelogram. You can prove this by dividing the parallelogram into two triangles, and then using SAS (side angle side) to prove the triangles congruent, which leads to you showing the corresponding angles are the same measure, therefore the other set of sides must be parallel as well.
Or
If the non parallel sides are the same length, then you have an isosceles trapezoid. A trapezoid is any figure with exactly one pair of parallel sides. An isosceles trapezoid is one where the non-parallel sides are the same length. The non-parallel sides are sometimes considered the legs of the trapezoid (and the parallel sides are the bases).
Or
If you have two adjacent sides that are same length, and you have one set of parallel sides, then you could have a trapezoid (not isosceles but just a more generalized trapezoid)
A=#nickels, b=#quarters
5a + 25b = 410 total value
5(a + 5b) = 410
a + 5b = 82
a + b = 30 total no. of coins
subtracting . . . 4b = 52
thus b = 13 and a = 17
13 quarters and 17 nickels = 13*25 + 17*5 = 410 = $4.10
The remainder would be 246.78
76 255/ 309 = 246.7799
(Rounding involved at top btw)
3/5, im working on the same stuff
diameters of circles and stuff no promblamo lol<span />
