Answer:
sin Ф = 3/√13; cos Ф = 2/√13; and tan Ф = 3/2
Step-by-step explanation:
Let's assume we're limiting ourselves to Quadrant I.
Start with the tangent function. tan Ф = opp / adj.
In this case opp = 3 and adj = 2.
The length of the hypotenuse is found using the Pythagorean Theorem and is √(3² + 2²) = √13.
Then sin Ф = opp / hyp = 3/√13 or 3√13/13
and
cos Ф = adj / hyp = 2/√13 or 2√13/13
and (as before)
tan Ф = opp / adj = 3/2
Graph each points:
f(x) = -13x + 1
when x = 0, y = 1
f(0) = -13(0) + 1
f(0) = 0 + 1
f(0) = 1
when x = 1, y = -14
f(1) = -13(1) + 1
f(1) = -13 + 1
f(1) = -14
when x = 2, y = -25
f(2) = -13(2) + 1
f(2) = -26 + 1
f(2) = -25
etc.
Graph each point and connect them.


To solve these type of problems you need to use the pythagoras theorem ⇨ Hypotenuse² = Base² + Altitude².
Here,
- Altitude = 1.6 cm.
- Base = 1.2 cm
- Hypotenuse = x
Now, let's solve for x.
Hypotenuse² = Base² + Altitude²
x² = (1.2)² + (1.6)²
x² = 1.44 + 2.56
x² = 4
x = √4
x = <em><u>2</u></em><em><u>.</u></em>
- So, the value of x is <em><u>2</u><u> </u><u>cm.</u></em>
<h3>
<u>NOTE</u><u> </u><u>:</u><u>-</u></h3>
- Pythagoras theorem can be used only in the cases of right-angled triangles. Here, it's given that the triangle is right angled so we can use this theorem.
- To solve the squares if decimals, take them as whole numbers & then just add the decimal points. For example, ⇨ for (1.2)², take it as 12² , then multiply 12 by 12, you'll get 144. Now, add the decimal place accordingly ⇨ 1.44 . So, (1.2)² = 1.44.