Answer:
For Month 1, we have:
Carry-over balance = $12,000.00
Finance charge = $189.90
New balance = $12,189.90
Minimum payment = $609.50
For Month 2, we have:
Carry-over balance = $11,580.41
Finance charge = $183.26
New balance = $11,763.66
Minimum payment $588.18
Step-by-step explanation:
Note: This question is not complete. The complete question is therefore provided before answering the question. See the attached pdf file for the complete question.
The explanation to the answer is now given as follows:
Note: See the attached excel file for calculations of the finance charge, carry-over balance, and minimum payment required for each of the next two months.
In the attached excel file, the following formulas are used:
r = Monthly percentage rate = APR / 12 = 18.99% / 12 = 1.5825%
Carry-over balance of the current month = New balance of the previous month - Minimum payment of the previous month
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xlsx
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<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
pdf
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Answer:
m = v + 2
Step-by-step explanation:
m is Mags, and v is Vector
m (Mags' age) = v(Vector's age) + 2
Work is provided in the image attached.
9. You need an exact answer. So I will give you it but I'll also give you an approximation because it might help you understand it more.
Because we know the cosine fo theta, we can evaluate the inverse cosine of -2/3 first to find theta.
= 131.81° approx.
Because 131.81° is in the second quadrant its third quadrant partner is 228.19°. Which would make the sine 0.75 approximately.
But we need an exact answer I suppose so which is this disgusting mess...
. I know it looks scary but it is basically all the steps we just did but without evaluating anything.
This can be simplified using: sin(x− y) = sinxcosy−cosxsiny
To... ![-sin(cos^{-1}(\frac{-2}{3}))](https://tex.z-dn.net/?f=-sin%28cos%5E%7B-1%7D%28%5Cfrac%7B-2%7D%7B3%7D%29%29)
answer: ![-sin(cos^{-1}(\frac{-2}{3}))](https://tex.z-dn.net/?f=-sin%28cos%5E%7B-1%7D%28%5Cfrac%7B-2%7D%7B3%7D%29%29)
10. Okay. So because we have a point we can say that...
θ = ![tan^{-1}(-9/11)](https://tex.z-dn.net/?f=tan%5E%7B-1%7D%28-9%2F11%29)
sin(θ) = +sin(
)
11. arcsin(-0.37) =
= -21.72°+2kπ or 201.72°+2kπ approx. where k has to be an integer
answer: idk if you want one or more solutions so I gave you them all.
12. arccos(-√3/2) = ![cos^{-1}(\frac{-\sqrt{3} }{2}) = \frac{5\pi }{6}+2k\pi, \frac{7\pi }{6}+2k\pi](https://tex.z-dn.net/?f=cos%5E%7B-1%7D%28%5Cfrac%7B-%5Csqrt%7B3%7D%20%7D%7B2%7D%29%20%3D%20%5Cfrac%7B5%5Cpi%20%7D%7B6%7D%2B2k%5Cpi%2C%20%5Cfrac%7B7%5Cpi%20%7D%7B6%7D%2B2k%5Cpi)
Remember that "k" must be an integer.
answer: 5π/6