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patriot [66]
3 years ago
6

The scatter plot shown gives the relationship between weekly pizza orders and the price per pizza, along with the line of best f

it. About what price is predicted when the demand is five pizzas?
I'm not sure of the answer ,and I'm not that good with graphs.So thanks for help ,who ever responds :)

Here's the answer choices:


A) $4.00


B) $5.00


C) $6.00


D) $7.00

Mathematics
2 answers:
Bess [88]3 years ago
7 0

Answer:

The answer is $5.

Step-by-step explanation:

When the demand is five pizzas, the $5 is predicted as the line is passing close to the $5 mark.

A line of best fit or also called the trend line is a straight line that may pass through some of the points, none of the points, or all of the points.

UNO [17]3 years ago
5 0
Based on your plot points, the best answer seems to be B) $5.00 

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Step-by-step explanation:

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<em>From the graph, the x intercept =9. Hence the equation of the given line is x = 9</em>

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Which expression is equivalent to 8g + 2 + 4g − 2 − 2g?
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4 0
2 years ago
Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete
Katyanochek1 [597]

Answer:

  1. b/a
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  3. n¹⁰/(16m⁶)
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Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

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1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

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2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

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3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

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4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

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5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

3 0
3 years ago
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