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3 years ago

Whats anothor name for eq

Mathematics

2 answers:

Neko [114]3 years ago

5 0

I think it’s just equation

Katarina [22]3 years ago

4 0

Equation? It would be math problem

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You are riding the swings at a fair. What are the coordinates of your location after a rotation of 180°?

nekit [7.7K]

Answer:

(6, -3)

Step-by-step explanation:

The actual coordinates are x = -6 and y = 3

If we rotate 180 degrees and the center of rotation is at (0,0), all we need to do is invert the signal of each axis, that is, we invert the sign of the original x-coordinate and invert the signal of the original y-coordinate.

So the final x-coordinate is - (-6) = 6

And the final y-coordinate is - (3) = -3

So the coordinates will be (6, -3).

5 0

4 years ago

A pair of equations is shown below.

7nadin3 [17]

3x − y = 9
y = −2x + 11

3x − (−2x + 11) = 9
3x + 2x - 11 = 9
5x = 9 + 11
5x = 20
x = 4

y = −2x + 11 = -2*4+11 = 3

(4, 3)

4 0

3 years ago

Read 2 more answers

9 times a number has 1 subtracted from it. The result is trebled. The answer is the same if you add 7 to twice the number and mu

Natali [406]

Answer: 4

Step-by-step explanation: 1) You need to first understand the question and a way to do that is to list plainly the information given.

2) Let the number be (X)

3) For the equation from the first sentence given; 3(9x-1)

4) From the second sentence; 7(7+2x)

5) Equating both sentences together, since the question says they are the same 3(9x-1) = 7(7+2x)

6) Opening the bracket/expanding the equation.... 27x-3=49+14x

Solving further we will have 13x = 52

X= 52/13

= 4

3 0

3 years ago

Read 2 more answers

The portion of the parabola y²=4ax above the x-axis, where is form 0 to h is revolved about the x-axis. Show that the surface ar

castortr0y [4]

Answer:

See below for Part A.

Part B)

$\displaystyle h=\Big(\frac{125}{\pi}+27\Big)^\frac{2}{3}-9\approx7.4614$

Step-by-step explanation:

Part A)

The parabola given by the equation:

$y^2=4ax$

From 0 to h is revolved about the x-axis.

We can take the principal square root of both sides to acquire our function:

$y=f(x)=\sqrt{4ax}$

Please refer to the attachment below for the sketch.

The area of a surface of revolution is given by:

$\displaystyle S=2\pi\int_{a}^{b}r(x)\sqrt{1+\big[f^\prime(x)]^2} \,dx$

Where r(x) is the distance between f and the axis of revolution.

From the sketch, we can see that the distance between f and the AoR is simply our equation y. Hence:

$r(x)=y(x)=\sqrt{4ax}$

Now, we will need to find f’(x). We know that:

$f(x)=\sqrt{4ax}$

Then by the chain rule, f’(x) is:

$\displaystyle f^\prime(x)=\frac{1}{2\sqrt{4ax}}\cdot4a=\frac{2a}{\sqrt{4ax}}$

For our limits of integration, we are going from 0 to h.

Hence, our integral becomes:

$\displaystyle S=2\pi\int_{0}^{h}(\sqrt{4ax})\sqrt{1+\Big(\frac{2a}{\sqrt{4ax}}\Big)^2}\, dx$

Simplify:

$\displaystyle S=2\pi\int_{0}^{h}\sqrt{4ax}\Big(\sqrt{1+\frac{4a^2}{4ax}}\Big)\,dx$

Combine roots;

$\displaystyle S=2\pi\int_{0}^{h}\sqrt{4ax\Big(1+\frac{4a^2}{4ax}\Big)}\,dx$

Simplify:

$\displaystyle S=2\pi\int_{0}^{h}\sqrt{4ax+4a^2}\, dx$

Integrate. We can consider using u-substitution. We will let:

$u=4ax+4a^2\text{ then } du=4a\, dx$

We also need to change our limits of integration. So:

$u=4a(0)+4a^2=4a^2\text{ and } \\ u=4a(h)+4a^2=4ah+4a^2$

Hence, our new integral is:

$\displaystyle S=2\pi\int_{4a^2}^{4ah+4a^2}\sqrt{u}\, \Big(\frac{1}{4a}\Big)du$

Simplify and integrate:

$\displaystyle S=\frac{\pi}{2a}\Big[\,\frac{2}{3}u^{\frac{3}{2}}\Big|^{4ah+4a^2}_{4a^2}\Big]$

Simplify:

$\displaystyle S=\frac{\pi}{3a}\Big[\, u^\frac{3}{2}\Big|^{4ah+4a^2}_{4a^2}\Big]$

FTC:

$\displaystyle S=\frac{\pi}{3a}\Big[(4ah+4a^2)^\frac{3}{2}-(4a^2)^\frac{3}{2}\Big]$

Simplify each term. For the first term, we have:

$\displaystyle (4ah+4a^2)^\frac{3}{2}$

We can factor out the 4a:

$\displaystyle =(4a)^\frac{3}{2}(h+a)^\frac{3}{2}$

Simplify:

$\displaystyle =8a^\frac{3}{2}(h+a)^\frac{3}{2}$

For the second term, we have:

$\displaystyle (4a^2)^\frac{3}{2}$

Simplify:

$\displaystyle =(2a)^3$

Hence:

$\displaystyle =8a^3$

Thus, our equation becomes:

$\displaystyle S=\frac{\pi}{3a}\Big[8a^\frac{3}{2}(h+a)^\frac{3}{2}-8a^3\Big]$

We can factor out an 8a^(3/2). Hence:

$\displaystyle S=\frac{\pi}{3a}(8a^\frac{3}{2})\Big[(h+a)^\frac{3}{2}-a^\frac{3}{2}\Big]$

Simplify:

$\displaystyle S=\frac{8\pi}{3}\sqrt{a}\Big[(h+a)^\frac{3}{2}-a^\frac{3}{2}\Big]$

Hence, we have verified the surface area generated by the function.

Part B)

We have:

$y^2=36x$

We can rewrite this as:

$y^2=4(9)x$

Hence, a=9.

The surface area is 1000. So, S=1000.

Therefore, with our equation:

$\displaystyle S=\frac{8\pi}{3}\sqrt{a}\Big[(h+a)^\frac{3}{2}-a^\frac{3}{2}\Big]$

We can write:

$\displaystyle 1000=\frac{8\pi}{3}\sqrt{9}\Big[(h+9)^\frac{3}{2}-9^\frac{3}{2}\Big]$

Solve for h. Simplify:

$\displaystyle 1000=8\pi\Big[(h+9)^\frac{3}{2}-27\Big]$

Divide both sides by 8π:

$\displaystyle \frac{125}{\pi}=(h+9)^\frac{3}{2}-27$

Isolate term:

$\displaystyle \frac{125}{\pi}+27=(h+9)^\frac{3}{2}$

Raise both sides to 2/3:

$\displaystyle \Big(\frac{125}{\pi}+27\Big)^\frac{2}{3}=h+9$

Hence, the value of h is:

$\displaystyle h=\Big(\frac{125}{\pi}+27\Big)^\frac{2}{3}-9\approx7.4614$

8 0

3 years ago

Read 2 more answers

The Coffee Spot recently served 12 pastries, including 3 bran muffins. Considering this data, how many of the next 16 pastries s

Goshia [24]

Answer:

Number of bran m muffins in 16 pastries = 4 bran muffins

Step-by-step explanation:

Given:

Total number of pastries = 12

Bran muffins (Include) = 3

Find:

Number of bran m muffins in 16 pastries.

Computation:

⇒ Ratio of bran muffins to total pastries = 3 / 12

⇒ Ratio of bran muffins to total pastries = 1 / 4

⇒ Ratio of bran muffins to total pastries = 0.25

Number of bran m muffins in 16 pastries = Number of total pastries × Ratio of bran muffins to total pastries

⇒ Number of bran m muffins in 16 pastries = 16 × 0.25

⇒ Number of bran m muffins in 16 pastries = 4 bran muffins

3 0

3 years ago