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yanalaym [24]
3 years ago
5

Please help I will give brainliest:) hurry! Answer carefully plss

Mathematics
1 answer:
Keith_Richards [23]3 years ago
3 0

Y = -3x^2 +4 is the answer to this problem

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Quadrilateral ABCD is located at A(−2, 2), B(−2, 4), C(2, 4), and D(2, 2). The quadrilateral is then transformed using the rule
quester [9]

Given vertices of the Quadrilateral ABCD :

A(−2, 2),

B(−2, 4),

C(2, 4), and

D(2, 2).

The quadrilateral is then transformed using the rule (x − 2, y + 8).

Let us find the coordinate  A', B', C', and D' by rule (x − 2, y + 8).

A(−2, 2) ---> (-2-2 , 2+8) = (-4, 10)

B(−2, 4) ---> (-2-2, 4+8) = (-4, 12)

C(2, 4), ---> ( 2-2, 4+8) = (0, 12)

D(2, 2) ---> (2-2, 2+8) = (0, 10).

So, <u>the coordinates of A', B', C', and D' are </u>

<u>A'(-4, 10), B'(-4, 12), C'(0, 12), and D'(0, 10).</u>

For the new coordinates we get we can say that each of the coordinate A', B', C', and D' moved 2 unit left and 8 units up.


4 0
3 years ago
Read 2 more answers
Stewart School has 178 computers. Grade 3 has 58 computers and flgrade 4 has 57 computers. What equations can be used to find ho
Ilya [14]

Answer: x=58+57=115

y=178-115=63


Step-by-step explanation:

Let x be the number of computers Grade 3 and grade 4 has and y be the numbers of computers the rest of school has.

Then, x= Grade 3 computers +Grade 4 computers.

\Rightarrow\ x=58+57=115

And y = Total computers - x

\Rightarrow\ y=178-115=63

Therefore, The  equations can be used to find how many computers the rest of the school has.

x=58+57=115

y=178-115=63



7 0
4 years ago
One year, the population of a city was 150,000. Several years later it was 171,000. Find the percent increase.
Naya [18.7K]

Answer:

15

Step-by-step explanation:

One year, the population of a city was 150,000. Several years later it was 171,000. Find the percent increase.

4 0
3 years ago
Read 2 more answers
P=$222 r=12% Y=10 A=?
sergey [27]
To solve for the A or the principal amount plus interest you can use two formulas:

A = P + I

Where: P = Principal
             I  = Interest

or you can use 

A = P (1+ rt)

Where: P = principal
             r  = rate in decimal
             t  = time in years

With your given you can use the second one, without having to use the first. 
Given that the Principal amount is $222 and the rate is 12% and time is 10 years, we first need to convert your rate into decimal by dividing the value in percent by 100 which will yield 0.12. 

Then now we can just input the data that you know into the formula:
A = P(1+ rt)
   = $222(1 + (0.12)(10))
   = $222(2.2) 
   = $488.40

Your A is then equal to $488.40

If you need to get the simple interest all you need to use is the first formula given:

A = P + I
for the interest you transpose the P to the side of the A and you will get:
I = A - P
  = $488.40 - $222
  = $266.40

$266.40 is the added interest to the principal amount. 
7 0
3 years ago
How are the numbers 21 and 2,100 alike?
Neko [114]
They both have 2 and a 1 in them .                                     \\\                                               
3 0
3 years ago
Read 2 more answers
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