The volume of a pyramid is V = 1/3 x base length^2 x height
Let X = base length.
We are told the height is 1/2 the length, so height would be 1/2x
Now we have:
972 = 1/3 * x^2 * 1/2x
Simplifying we get:
972 = 1/6x^3
Multiply both sides by 6:
5832 = x^3
Take the cube root of both sides:
x = 18
The length of the base is 18 inches.
The height is 1/2 that, so the height would be 18/2 = 9 inches.
Answer:
The lines are parallel only if:
x-1 = 63
or, x = 64 degrees
First, you want to establish your equations.
L=7W-2
P=60
This is what we already know. To find the width, we have to plug in what we know into P=2(L+W), our equation to find perimeter.
60=2(7W-2+W)
Now that we only have 1 variable, we can solve.
First, distribute the 2.
60=14W-4+2W
Next, combine like terms.
60=16W-4
Then, add four to both sides.
64=16W
Lastly, divide both sides by 16
W=4
To find the length, we plug in our width.
7W-2
7(4)-2
28-2
L=26
Answer:
6/12, 8/12, and 9/12.
Step-by-step explanation:
Let's find the least common denominator:
First, the least common multiple of 2, 3, and 4 is 12.
12 is divisible by 2, 3, and 4.
<u>Next, multiply the denominators with the numerators:</u>
Products: 6/12, 8/12, and 9/12
