The probability that only one shows a 2.
There are 36 different outputs (6x6) = 36
There are 6 combinations where the first cube shows a 2, these are 2,1;2,2;2,3;2,4;2,5; and 2.6
There are 6 combinations where the second cube shows a 2: 1,2;2,2;3,2;4,2;5,2; and 6,2.
Of those one combination on each set shows two 2.
Then the number of combinations with only one 2 are 6 - 1 + 6 -1 = 10
Now the probabilit is 10 out of 36 = 10 / 36 = 5 / 18
Answer:
C , 30 N
Step-by-step explanation:
Answer:
15,17,19
Step-by-step explanation:
Make an equation : ![x+(x+2)+(x+4)=51](https://tex.z-dn.net/?f=x%2B%28x%2B2%29%2B%28x%2B4%29%3D51)
Solve the equation:![3x+6=51](https://tex.z-dn.net/?f=3x%2B6%3D51)
![3x=51-6](https://tex.z-dn.net/?f=3x%3D51-6)
![3x=45](https://tex.z-dn.net/?f=3x%3D45)
![x=15](https://tex.z-dn.net/?f=x%3D15)
Since x=15 then the second number is 17 and then 19
Hope this helps!
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3: 8h+24 4: 6h+21 5: 15x+45y 6: 44h+12g
7: 7jk first box 12jm second box. 8: 9ab+13a
Basically you just want to multiply the number outside the parentheses to each number inside them.