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Allushta [10]
3 years ago
6

Fill in the blank with numbers that make the statement true.

Mathematics
2 answers:
Arisa [49]3 years ago
7 0

Answer:

12+(-12)=0

-14+34=20

-65+42=-23

Delvig [45]3 years ago
6 0
12 + -12 equals 0
-13+34 equals 20
And the last ones answer is -23
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A sample of ore is found to be 
Kitty [74]
.83% is the answer osdndksnsjfbbdbddh
4 0
2 years ago
Read 2 more answers
The score on an exam from a certain MAT 112 class, X, is normally distributed with μ=78.1 and σ=10.8.
salantis [7]

a) X

b) 0.1539

c) 0.1539

d) 0.6922

Step-by-step explanation:

a)

In this problem, the score on the exam is normally distributed with the following parameters:

\mu=78.1 (mean)

\sigma = 10.8 (standard deviation)

We call X the name of the variable (the score obtained in the exam).

Therefore, the event "a student obtains a score less than 67.1) means that the variable X has a value less than 67.1. Mathematically, this means that we are asking for:

X

And the probability for this to occur can be written as:

p(X

b)

To find the probability of X to be less than 67.1, we have to calculate the area under the standardized normal distribution (so, with mean 0 and standard deviation 1) between z=-\infty and z=Z, where Z is the z-score corresponding to X = 67.1 on the s tandardized normal distribution.

The z-score corresponding to 67.1 is:

Z=\frac{67.1-\mu}{\sigma}=\frac{67.1-78.1}{10.8}=-1.02

Therefore, the probability that X < 67.1 is equal to the probability that z < -1.02 on the standardized normal distribution:

p(X

And by looking at the z-score tables, we find that this probability is:

p(z

And so,

p(X

c)

Here we want to find the probability that a randomly chosen score is greater than 89.1, so

p(X>89.1)

First of all, we have to calculate the z-score corresponding to this value of X, which is:

Z=\frac{89.1-\mu}{\sigma}=\frac{89.1-78.1}{10.8}=1.02

Then we notice that the z-score tables give only the area on the left of the values on the left of the mean (0), so we have to use the following symmetry property:

p(z>1.02) =p(z

Because the normal distribution is symmetric.

But from part b) we know that

p(z

Therefore:

p(X>89.1)=p(z>1.02)=0.1539

d)

Here we want to find the probability that the randomly chosen score is between 67.1 and 89.1, which can be written as

p(67.1

Or also as

p(67.1

Since the overall probability under the whole distribution must be 1.

From part b) and c) we know that:

p(X

p(X>89.1)=0.1539

Therefore, here we find immediately than:

p(67.1

7 0
3 years ago
A number greater than -5
Serggg [28]

Answer:

Hi there!

Your answers are:

1) x> 5

Some numbers that would fit this equation are 6, 7, 8, etc!

2) x<= 30

Some numbers that would fit this are 30, 29, 28, etc!

3) x>= 17

Some numbers that would fit this equation are 17, 18, 19, etc!

4) x>= 90

Some numbers that would fit this are 90, 91, 92, etc!

Hope this helps!

5 0
3 years ago
PLEASE HELP ME!!!!!!!
Evgesh-ka [11]
Monday $2000 Tuesday $1800 wendsday $ 1440 thursday $5670
8 0
3 years ago
PLEASE ANSWER CORRECTLY
inn [45]

Answer:

$76.32

Step-by-step explanation:

First, add up all the costs for everything:

17 + 30 + 25 = 72

Now, we need to add the sales tax. To do this we multiply 72 by 1.06. This is because the sales tax is 6% (the decimal form of 6% is 0.06), and we add it on to the 100% cost (which is 1 in decimal form).

(72)(1.06) = 76.32

Therefore the total cost of everything Walter bought plus the tax rate is $76.32.

<em>I hope this helps!!</em>

<em>- Kay :)</em>

7 0
2 years ago
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