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Free_Kalibri [48]
3 years ago
7

Question 11 of 11 -

Mathematics
1 answer:
alex41 [277]3 years ago
6 0

Answer:

AA similarity

Step-by-step explanation:

Your question is not well presented.

See attachment

Given

Triangles ABC and DBE

Required

Which postulate supports the similarities of ABC and DBE

At the first transformation (180 degrees rotation) both triangles maintain SSS and AAA relationships. i.e <em>Side-Side-Side</em> and <em>Angle-Angle-Angle</em>

This is so because rotations do not alter the side lengths; neither does it alter the angles.

When the second transformation (dilation) takes place, the lengths of both triangles ABC and DBE become different because dilation alters side lengths.

However, angle measurements remain unaltered.

<em>Hence, AAA similarity answers the question</em>

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b. Principal: the amount of money you initially invested

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Which of the aaa-values satisfy the following inequality?
mina [271]

Answer:

a = 3

Step-by-step explanation:

When you add the given value for a with 7, the resulting answer must be less than 11.

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Professor Green is interested in determining the average SAT score for the entire population of individuals who took the SAT. Sh
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Select the correct answer from each drop-down menu.
Alenkasestr [34]

Answer:

The points of intersections are: <u>(1.5 , 1.25) and (4 , 0)</u>

Step-by-step explanation:

Given:

y = x² - 6x + 8   ⇒ (1)

2y + x = 4         ⇒ (2)

And required the solution of the system of equations.

By graphing the system of equations, the points of intersections are:

<u>(1.5 , 1.25) and (4 , 0)</u>

See the attached figure.

<u>Another solution:</u>

By substitution of y from the second equation at the first equation.

From (1) ⇒ y = 0.5 (4-x)

At (2): and solve for x

0.5 ( 4 - x ) = x² - 6x + 8 ⇒ multiply both sides by 2

4 - x = 2x² - 12x + 16

2x² - 12x + 16 + x - 4 = 0

2x² - 11x + 12 = 0

The general solution of the quadratic equation:

x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

so, a = 2 , b = -11 and c = 12

∴x=\frac{-(-11) \pm \sqrt{(-11)^2-4*2*12} }{2*2}=\frac{11 \pm \sqrt{25} }{4} =\frac{11 \pm 5}{4} \\x = \frac{11+5}{4} = \frac{16}{4}=4\\  OR \  x = \frac{11-5}{4}=\frac{6}{4}=1.5\\

∴ at x = 4       ⇒ y = 0.5 (4-x) = 0.5 * 0 = 0

And at x = 1.5 ⇒ y  = 0.5 (4-x) = 0.5 * ( 4 - 1.5 ) = 0.5 * 2.5 = 1.25

<u>So, the solution are the points (4,0) and (1.5 , 1.25)</u>

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3 years ago
Find the slope of (-2,-5) and (8,-5) And find the slope of the line passing through the points (4,9) and (4,-7)
DochEvi [55]

Answer:

Part 1) m=0

Part 2) The slope is undefined

Step-by-step explanation:

we know that

The formula to calculate the slope between two points is equal to

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Part 1

we have

A(-2,-5)\ B(8,-5)

Substitute the values

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Part 2

we have

A(4,9)\ B(4,-7)

Substitute the values

m=\frac{-7-9}{4-4}

m=\frac{-16}{0}   ----> is a vertical line (parallel to y-axis)

The slope is undefined

7 0
4 years ago
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