| -6x - 3 | > 15
This expression can be written as:
a) -6x - 3 > 15
b) -15 > - 6x - 3
Solving a part:
Solving b part:
or we can write:
x > 2
So the solution to given inequality is:

The second option correctly lists this solution.
642 ion wanna show the work good luck doe
Answer:
see explanation
Step-by-step explanation:
Given
(a + bi)(a - bi) ← expand using FOIL
= a² - abi + abi - b²i² → i² = - 1
= a² + b²
Since a and b are any real numbers, then
a² + b² is a real number
B
When a complex number is multiplied by its conjugate the result is always real.
Multiplying by 2 is the rule...plz mark me as brainliest as just joined!
Answer:
I think that CPCTC is the correct answer.
It is the abbreviation for the congruence postulate.