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ValentinkaMS [17]
3 years ago
6

Write an explicit formula for the following sequence. Then generate the first five terms.

Mathematics
1 answer:
ivann1987 [24]3 years ago
7 0
Nth term an  = a1 r^(n-1) 
                    = 512 (0.5)^(n-1)   Answer

First 5 terms are:-

 512 , 256 , 128, 64 , 32
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Mary has used 160 tiles to cover 40% of the back splash in her kitchen how many tiles will it take to cover the entire back spla
dangina [55]

Answer:

400 tiles :)

Step-by-step explanation:

2/5 = 160/x

1/5 = 80/x

80 *5 = 400

6 0
3 years ago
Write the equation of the line that passes through the points (1, -7) and (-6, -9).
jek_recluse [69]

Answer:

y = 2/7 x - 51/7

Step-by-step explanation:

Equation of the line

(y-y1)/(y2-y1) = (x-x1)/(x2-x1)

(y-(-7)/(-9-(-7) = (x-1)/(-6-1)

(y+7)/-2 = (x-1)/-7

(-y-7)/2 = (-x+1)/7

-y-7 = -2/7 x + 2/7

-y = -2/7x +2/7 + 7

y = 2/7 x - 2/7 - 7

y = 2/7 x + (-2-49)/7

y = 2/7 x - 51/7

3 0
3 years ago
What is the slope of the line that passes through the points (-20, 18) and (30, 14)?
Nikolay [14]

Answer:

-\frac{2}{25}

Step-by-step explanation:

slope is the change in y over the change in x.

change in y is 14-18= -4

change in x is 30-(-20)= 50

so the answer is -4/50

we can factor out 2 from both equations to simplify the fraction. this gives us -2/25

6 0
2 years ago
Solve with cramer's rule x+2y+3z=11, 2x+y+2z=10, 3x+2y+z=9
nalin [4]

Answer:

x = 2 , y = 0 , z = 3

Step-by-step explanation:

Cramer's rule is a rule through which we can find the solution of linear equation.

we have the three linear equations as

x+2y+3z=11

2x+y+2z=10

3x+2y+z=9

AX=B  

A: coefficient matrix

X= unknown vectors(x,y,z)

D = values of the linear equation (11 , 10 , 9)

now we find the determinant of the given linear equation

determinant of the matrix will be

A = \left[\begin{array}{ccc}1&2&3\\2&1&2\\3&2&1\end{array}\right]  = 1(1-4) - 2(2-6) + 3(4 - 3)

                    = 1(-3) - 2(-4) + 3(1)

                    = -3+8+3 = 8

also D\neq 0

so the determinant is Non zero we can apply Cramer's rule

we will be replacing the first column of the coefficient matrix A with the values of D

by replacing the first column we will get the value of the variable 'x'

Dx =  \left[\begin{array}{ccc}11&2&3\\10&1&2\\9&2&1\end{array}\right]   = 11(1-4) -2(10-18) + 3(20-9) = -33+16+33 = 16

x = \frac{Dx}{D}  = \frac{16}{8} = 2

similarly

Dy = \left[\begin{array}{ccc}1&11&3\\2&10&2\\3&9&1\end{array}\right] = 1(10-18) -11(2-6) + 3(18 -30) = -8 +44 -36 = 0

y = \frac{Dy}{D} = 0

Dz= \left[\begin{array}{ccc}1&2&11\\2&1&10\\3&2&9\end{array}\right] = 1(9 - 20) -2(18 - 30) + 11(4 -3) = -11 +24 +11 = 24

z = \frac{Dz}{D} = \frac{24}{8} = 3

so we have the solution as

x = 2 , y = 0 , z = 3

Therefore the solution for the given linear equations is (2,0,3).

3 0
2 years ago
Y=-2x-21 determine the intercepts of the line (,) (,) ASAPPPP
Nesterboy [21]

Answer:

x intercept (10.5,0)

y intercept (0, -21)

Step-by-step explanation:

y=-2x-21

there are two intercept for a line

x intercept, the point of given equation of  line which lies on x axis.

For x intercept corodinate of y is o

Thus, value x intercept is form (x,0)

putting these value in y=-2x-21, we find x intercept

0=-2x-21

2x = 21

x = 21/2 = 10.5

Thus, x intercept (10.5,0)

Y intercept, the point of given equation of  line which lies on y axis.

For Y intercept coordinate of x is o

Thus, value y intercept is form (0,y)

putting these value in y=-2x-21, we find y intercept

y = -2*0 -21

y = -21

Thus, y intercept (0, -21)

5 0
3 years ago
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