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2 answers:
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For this case what we should do is take into account the following vectors:
We must find the following subtraction of vectors:
Subtracting component to component we have:
By writing we have:
Then the module of the resulting vector is given by:
Rewriting we have:
Answer:
The module of the resulting vector is given by:
option B
Answer:
(-1, -2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
- Solving systems of equations by graphing
Step-by-step explanation:
<u>Step 1: Define Systems</u>
-2x + y = 0
5x + 3y = -11
<u>Step 2: Rewrite Systems</u>
-2x + y = 0
- Add 2x on both sides: y = 2x
<u>Step 3: Redefine Systems</u>
y = 2x
5x + 3y = -11
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 5x + 3(2x) = -11
- Multiply: 5x + 6x = -11
- Combine like terms: 11x = -11
- Isolate <em>x</em>: x = -1
<u>Step 5: Solve for </u><em><u>y</u></em>
- Define equation: y = 2x
- Substitute in <em>x</em>: y = 2(-1)
- Multiply: y = -2
<u>Step 6: Graph Systems</u>
<em>Check the solution set.</em>
