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vesna_86 [32]
3 years ago
13

PLEASE HELP!!!!!!!What has to be true if you want to solve a quadratic?

Mathematics
1 answer:
Dmitrij [34]3 years ago
7 0

Answer:

Here you go

Step-by-step explanation:

The quadratic formula helps you solve quadratic equations, and is probably one of the top five formulas in math. Then the formula will help you find the roots of a quadratic equation, i.e. the values of x where this equation is solved.

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Solve the system of equations using elimination: 8x - 8y = 0 and<br> -5x - 7y= -12.
Lena [83]

Answer:

My answers were (1,1) for both lmk if it works ;)

Step-by-step explanation:

5 0
2 years ago
Amanda composed two songs. The longer song is 126 seconds less than twice the length of the short song. The longer song lasts 28
polet [3.4K]
If there are two songs written and the longest one is 126 seconds less than twice the length of the short song, and the longest one lasts 286 seconds, then the shorter song's length can be found using this formula: 
2x-126=286.
This would then turn into x-63=143 to show the time difference. Solving here for x, would be 206 seconds.
4 0
3 years ago
Which of these statements is true for f(x)=(1/10)^x
lana66690 [7]

Step-by-step explanation:

Considering the function

f\left(x\right)=\:\left(\frac{1}{10}\right)^x

Analyzing option A)

Considering the function

f\left(x\right)=\:\left(\frac{1}{10}\right)^x

Putting x = 1 in the function

f\left(1\right)=\:\left(\frac{1}{10}\right)^1

f\left(1\right)=\:\left\frac{1}{10}\right

So, it is TRUE that when  x = 1 then the out put will be f\left(1\right)=\:\left\frac{1}{10}\right

Therefore, the statement that '' The graph contains \left(1,\:\frac{1}{10}\right)  '' is TRUE.

Analyzing option B)

Considering the function

f\left(x\right)=\:\left(\frac{1}{10}\right)^x

The range of the function is the set of values of the dependent variable for which a function is defined.

\mathrm{The\:range\:of\:an\:exponential\:function\:of\:the\:form}\:c\cdot \:n^{ax+b}+k\:\mathrm{is}\:\:f\left(x\right)>k

k=0

f\left(x\right)>0

Thus,

\mathrm{Range\:of\:}\left(\frac{1}{10}\right)^x:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(0,\:\infty \:\right)\end{bmatrix}

Therefore, the statement that ''The range of f(x) is y > \frac{1}{10} " is FALSE

Analyzing option C)

Considering the function

f\left(x\right)=\:\left(\frac{1}{10}\right)^x

The domain of the function is the set of input values which the function is real and defined.

As the function has no undefined points nor domain constraints.

So, the domain is -\infty \:

Thus,

\mathrm{Domain\:of\:}\:\left(\frac{1}{10}\right)^x\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

Therefore, the statement that ''The domain of f(x) is x>0 '' is FALSE.

Analyzing option D)

Considering the function

f\left(x\right)=\:\left(\frac{1}{10}\right)^x

As the base of the exponential function is less then 1.

i.e. 0 < b < 1

Thus, the function is decreasing

Also check the graph of the function below, which shows that the function is decreasing.

Therefore, the statement '' It is always increasing '' is FALSE.

Keywords: function, exponential function, increasing function, decreasing function, domain, range

Learn more about exponential function from brainly.com/question/13657083

#learnwithBrainly

3 0
4 years ago
Read 2 more answers
Graph it pleaseeeeeeeeeeeeeeeeeeeeeeeeeeee
mina [271]

Answer:

Step-by-step explanation:

5c + 4f ≥ 200

c + f ≤ 60

c > 0

f > 0

5 0
2 years ago
3. You want to have $4000 in your savings account after 2 years. Find the amount you should deposit for each of the situations d
pychu [463]

Answer:

Part A)

About $3767.34.

Part B)

About $3692.47.

Step-by-step explanation:

Part A)

Recall that compound interest is given by the formula:
\displaystyle A = P\left(1+\frac{r}{n}\right)^{nt}

Where <em>A</em> is the final amount, <em>P</em> is the initial amount, <em>r</em> is the interest rate, <em>n</em> is the number of times compounded per year, and <em>t</em> is the number of years.

To obtain $4000 after two years, let <em>A</em> = 4000 and<em> t</em> = 2.

Because the account pays 3% interest compounded monthly, <em>r</em> = 0.03 and <em>n</em> = 12.

Substitute and solve for <em>P: </em>

<em />\displaystyle \begin{aligned} (4000) & = P\left(1+\frac{(0.03)}{(12)}\right)^{(12)(2)} \\ \\ P & = \frac{4000}{\left(1+\dfrac{(0.03)}{(12)}\right)^{(12)(2)}} \\ \\ & \approx \$3767.34\end{aligned}

In concluion, about $3767.34 should be deposited.

Part B)

Recall the formula for continuous compound:

\displaystyle A = Pe^{rt}

Where <em>e</em> is Euler's number.

Hence, let <em>A</em> = 4000, <em>r</em> = 0.04 and <em>t</em> = 2. Substitute and solve for <em>P: </em>

<em />\displaystyle \begin{aligned}(4000) & = Pe^{(0.04)(2)} \\ \\ P & = \frac{4000}{e^{(0.02)(4)}} \\ \\ & \approx \$3692.47 \end{aligned}

In conclusion, about $3692.47 should be deposited.

8 0
2 years ago
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