Find the range of the relation.

Amber, Bernie, and Carlos are working on a problem together. Their goal is to correctly apply the difference of cubes formula to

NeX [460]

Answer: Carlos is correct

Step-by-step explanation:

2x^5-250x^2

The first step is to factorize out 2x^2

2x^2(x^3-125)

This can be rewritten as

2x^2(x^3-5^3),

Recall, difference if cube (a^3-b^3)

= (a-b)(a^2 +ab + b^2)

from our equation,

a= x

b = 5.

So the difference of cubes will be

2x^2[(x-5) (x^2 + 5x + 5^2)]

=2x^2[(x-5) (x^2 + 5x + 25)]

Carlos followed these steps. So he is correct. Carlos is correct because he correctly factored the GCF, identified a and b, and applied the difference of cubes method.

Amber is incorrect because 125 is equal to b3, not b.

Bernie is incorrect because x2 is not the GCF of the polynomial. The GCF is 2x^2.

6 0

3 years ago

If carpet cost $8 per square foot. How much money will it cost to put new carpet in all the rooms in the house?

Stolb23 [73]

How many feet is the room

6 0

3 years ago

Aadya and Ethan like playing with remote-control cars. There's a straight track at the

e-lub [12.9K]

The distance between the two cars is now 320 yards.

<h3 /><h3><u>Distances</u></h3>

To determine what is the distance between the two cars now if they did not collide the following calculation must be performed:

500 - (500 - 405) - (500 - 415) = X
500 - 95 - 85 = X
500 - 180 = X
320 = X

Therefore, the distance between the two cars is now 320 yards.

Learn more about distances in brainly.com/question/989117

8 0

3 years ago

Help solving this math question

olga_2 [115]

22. B) $65,000,000 per year.

23. B) Education.

Step-by-step explanation:

Step 1; To find the average rate of change in annual budget between the two given years. We divide the difference in values for the two years by the period in between the two years. In 2008, the budget was $358,708,000 while in 2010 it was $488,106,000. The period in between was 2 years i.e 2009 and 2010.

The average rate of change = $\frac{488,106,000-358,708,000}{2}$ = $\frac{129,398,000}{2}$ = $64,699,000 per year.

So the average rate of change was $64,699,000 which approximately equals option B. $65,000,000.

Step 2; To find the human resources program's 2007 to 2010 ratio we divide the value in 2007 to the value in 2010. To find the other similar ratio, we divide the value in 2007 to the value in 2010 for all the other programs and determine which is closest to the human resources program.

Human resources program ratio = $\frac{4,051,050}{5,921,379}$ = 0.6841,