Answer:
There are 8 true/false questions and 26 fill-in-the-blank questions.
Step-by-step explanation:
Let "t" be the number of 2-point true/false questions and "f" the number of 5-point fill-in-the-blank questions.
Mrs. Simmons gave a history test worth 92 points. Symbollically,
2 t + 5 f = 92 [1]
There were a total of 34 questions in the test. Symbollicaly,
t + f = 34
t = 34 - f [2]
If we replace [2] in 1, we get
2 (34 - f) + 5 f = 92
68 - 2 f + 5 f = 92
3 f = 24
f = 8
We replace f = 8 in [2],
t = 34 - 8 = 26
There are 8 true/false questions and 26 fill-in-the-blank questions.
Answer: 2 buses and 4 vans would be needed
Step-by-step explanation:
Let x represent the number of buses that would be needed.
Let y represent the number of vans that would be needed.
There will be six drivers, and two different types of vehicles. This means that
x + y = 6
142 students are going on a field trip. A bus can hold 51 people while a van can hold 10. This means that
51x + 10y = 142 - - - - - - - - - - - 1
Substituting x = 6 - y into equation 1, it becomes
51(6 - y) + 10y = 142
306 - 51y + 10y = 142
- 51y + 10y = 142 - 306
- 41y = - 164
y = - 164/ - 41
y = 4
x = 6 - y = 6 - 4
x = 2
Answer:
Step-by-step explanation:
The idea here is to get the left side simplified down so it is the same as the right side. Consequently, there are 3 identities for cos(2x):
,
, and

We begin by rewriting the left side in terms of sin and cos, since all the identities deal with sines and cosines and no cotangents or cosecants. Rewriting gives you:

Notice I also wrote the 1 in terms of sin^2(x).
Now we will put the numerator of the bigger fraction over the common denominator:

The rule is bring up the lower fraction and flip it to multiply, so that will give us:

And canceling out the sin^2 x leaves us with just
which is one of our identities.
<u>By substitution method </u>
5x - 3y =1
3x + 2y = 1
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I hope I helped you^_^