The problem deals with fractions comparison, lets do it:
21/30 > 2/3
we begin solving:
21 > (2/3)*30
21 > 2*10
<span>21 > 20
</span>therefore the proposed inequality is true, <span>21/30 > 2/3
You can solve as well getting same denominator for both fractions and comparing directly, in this case we need to get 2/3 to be divided by 30:
2/3 = (10/10)(2/3) = 20/30
So we have:
</span><span>21/30 > 2/3
</span>which is equal to:
<span>21/30 > 20/30
</span>and we compare directly because both fractions are divided by the same number, and we can see that the inequality is true.
Hello there!
If:
110....> 8 seconds
x........32 seconds
Cross multiply
8 * x = 32 * 110
8x = 3520
x = 3520/8
x= 440
It makes 440 rotations in 32 seconds
I hope this helps!
<span>100 = 5 * (5+5+5+5)
</span><span>100 = (5*5*5) - (5*5)
</span><span>100 = (55/.5) - (5+5)</span>
Rationalize both the numerator and denominator. Given
we can rationalize it by introducing conjugates of the numerator and denominator:
Then the limit is equivalent to
For the remaining expression, divide through uniformly by 
:
As <em>n</em> goes to infinity, the remaining terms containing <em>n</em> converge to 0, leaving
making the overall limit 3.
1s = 0.1s X 10
1 2/3 = 5/3
10 = 10/1
5/3 X 10/1 = 50/3 = 16 2/3 = 16.666m/s
