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Sergio039 [100]
3 years ago
15

An analysis of the grades on the first test in History 101 revealed that they approximate a normal curve with a mean of 75 and a

standard deviation of 8. The instructor wants to award the grade of A to the upper 10% of the test grades. To the nearest percent, what is the dividing point between an A and a B grade?
Select one:
a. 80
b. 85
c. 90
d. 95
Mathematics
1 answer:
QveST [7]3 years ago
3 0

Answer:

b. 85

Step-by-step explanation:

Average grade (μ) = 75

Standard deviation (σ) = 8

Assuming a normal distribution, the z-score corresponding to the upper 10% of the test grades is z = 1.28.

The minimum grade 'X' within the top 10% is given by:

z=\frac{X-\mu}{\sigma}\\1.28=\frac{X-75}{8}\\X=85.24

Rounding to the nearest percent, the dividing point between an A and a B grade is 85.

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nadezda [96]

Answer:

w = 2

Step-by-step explanation:

Distribute the expression and compare like terms with the simplified version.

Given

wx(3y² + 6y - 2) ← distribute parenthesis

= 3wxy² + 6wxy - 2wx

Compare coefficients of like terms with

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Compare xy² term, then

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w = 2

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Compare x term, then

- 2w = - 4 ( divide both sides by - 2 )

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Hence the required value of w is 2

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Watch closely.    I'll try to go slow.
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