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vazorg [7]
3 years ago
12

What is the missing number 12×1= 12+W​

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
4 0
W = 0
Twelve times one is 12 so 12+w has to equal 12
AfilCa [17]3 years ago
4 0

Answer:

Step-by-step explanation:

12×1 = 12+w

12 = 12 + w

w = 12 - 12

w = 0

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Bonjour pourriez vous m'aider avec cette équation du second degré? j'ai du mal à comprendre le concept. merci
olga_2 [115]

If a quadratic equation has solutions, the standard procedure will always work: given an equation like

ax^2+bx+c=0

The solutions (if any) are given by

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

In your case, you have

a=-9,\ b=0,\ c=1

So the formula becomes

x_{1,2} = \dfrac{\pm\sqrt{36}}{18}= \pm\dfrac{6}{18}=\pm\dfrac{1}{3}

Anyway, this is quite a special case, because you're missing the linear term (since b=0)

This means that you can solve equations like these more easily: rearrange the equation to make it look like ax^2=c. In your case, it becomes

9x^2=1

Divide both sides by 9:

x^2=\dfrac{1}{9}

Now, you know that the square of a number equals 1/9. By definition, it means that this number is the square root of 1/9. Nevertheless, both the square root and its opposite are solutions of the equation, because the minus sign will cancel out when squaring.

So, in general, you have

ax^2=c \iff x^2 = \dfrac{c}{a} \iff x=\pm\sqrt{\dfrac{c}{a}

which of course makes sense, if you're using real numbers, only if c/a>0.

In your case, this becomes

9x^2=1 \iff x^2 = \dfrac{1}{9} \iff x=\pm\sqrt{\dfrac{1}{9}} = \pm\dfrac{1}{3}

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3 years ago
A farmer grows watermelons and cantaloupes. Let X represent the weight of the watermelon, and let Y represent the weight of a ca
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Answer:

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Step-by-step explanation:

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Answer:

whats the answers available?

Step-by-step explanation:

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To find the range, you must subtract the maximum and the minimum. In this case you subtract 15 and 2. And you get 13. The range is 13
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