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MArishka [77]
3 years ago
12

√-14 x √18 Please write with steps

Mathematics
1 answer:
densk [106]3 years ago
4 0

Answer:

6i\sqrt{7}

Step-by-step explanation:

One can multiply the two radicles by multiplying the values under the radicals, then taking out perfect squares. In essence;

\sqrt{-14}{*\sqrt{18}\\

=\sqrt{(-14)(18)}

= \sqrt{-252}

Rewrite such that is expressed perfect square factors in the number,

\sqrt{(-1)(9)(4)(7)}

Take out the factors,

3 * 2*\sqrt{(-1)(7)}

Simplify,

6\sqrt{(-1)(7)}

Remember the square root of negative one can be signified by the character (i), therefore, one can take it out from the radical.

6i\sqrt{7}

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Vertical angles are congruent whether the lines are parallel or not.
Corresponding angles are congruent.
Alternate interior and alternate exterior angles are congruent.
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3 years ago
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Find the expansions of sin⁡5θ and cos⁡5θ in terms of sin⁡θ and cos⁡θ.
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\bf \textit{quad-angle identities}\\\\\\

cos(4\theta)=8cos^4(\theta)-8cos^2(\theta)+1
\\\\\\
sin(4\theta)=
\begin{cases}
8sin(\theta)cos^3(\theta)-4sin(\theta)cos(\theta)\\\\
4sin(\theta)cos(\theta)-8sin^3(\theta)cos(\theta)
\end{cases}\\\\
-----------------------------\\\\


\bf sin(5\theta)\iff sin(4\theta + \theta)
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sin(4\theta)cos(\theta)+cos(4\theta)sin(\theta)
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[4sin(\theta)cos(\theta)-8sin^3(\theta)cos(\theta)]cos(\theta)\\\\ + [8cos^4(\theta)-8cos^2(\theta)+1]sin(\theta)

\bf -----------------------------\\\\
cos(5\theta)\iff cos(4\theta + \theta)
\\\\\\
cos(4\theta)cos(\theta)-sin(4\theta)sin(\theta)\\\\\\\
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[4sin(\theta)cos(\theta)-8sin^3(\theta)cos(\theta)]sin(\theta)

distribute... and simplify :)

4 0
3 years ago
What is x in the expression 7x - 6
Eva8 [605]

Answer:

Variable

Step-by-step explanation:

I just know. You can search it up if you'd like!

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A) Work out an estimate for
SashulF [63]
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You take measurements of the distance traveled by an object that is increasing its speed at a constant rate. The distance travel
Serhud [2]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Given:

s_1 = 21 \ \  t_1 = 1\\\\s_2 = 59 \ \ t_2 = 2\\\\s_3 = 141 \ \  t_3 = 4

All points are on the graph including its quadratic function, in order to install their coordinates to values of x and y with the following values:

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3 years ago
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