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3 years ago

Please help last part to my question it's already late!

Mathematics

1 answer:

natita [175]3 years ago

6 0

Answer:

No, it's not.

Step-by-step explanation:

A right triangle has to have its edges have 90 degrees, and the triangle that they showed does not have that.

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(70 points)------------------

Reil [10]

I don’t understand chet

8 0

3 years ago

Read 2 more answers

Please help due ASAP <br> Show workings

Minchanka [31]

Answer:

WZ = 30

Step-by-step explanation:

set up equation based on WZ = W'Z'

3/4[6x + 10] = 13x - 35

multiply each side of equation by 4 to eliminate fractions:

18x + 30 = 52x - 140

-34x = -170

x = 5

substitute 5 for 'x' in either expression:

13(5) - 35

65 - 35 = 30

6 0

3 years ago

Read 2 more answers

A recipe for 11 pizza crust calls for 3838 tablespoon of salt. How much salt is needed to make 33 pizza crusts?

max2010maxim [7]

Its 11,514 tablespoons of salt

8 0

4 years ago

One of the legs of a right triangle measures 4 cm and its hypotenuse measures 18 cm. Find the measure of the other leg. If neces

Aleks04 [339]

Answer:

√308 or 17.5

Step-by-step explanation:

c^2=a^2+b^2

c^2-a^2=b^2

Substitute

18^2-4^2=b^2

324-16=b^2

b^2=308

b=√308 or b=17.5

7 0

3 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago