I apologize , but i do not see it. provide more
SA= Lateral Area+2(base)
Lateral Area=Perimeter x Height
Answer:
14.4 is your answer
Step-by-step explanation:
Answer:
Part 1)
Part 2)
Part 3)
Part 4)
Step-by-step explanation:
Part 1) HI = 3.9 and HJ = 6.2. Find IJ
we have that
I is between H and J
substitute the given values and solve for IJ
subtract 3.9 both sides
Rewrite
Part 2) JI = 25 and HI = 13. Find HJ
we have that
H is between I and J
remember that
IH=HI and IJ=JI
substitute the given values and solve for HJ
subtract 13 both sides
Rewrite
Part 3) H is the midpoint of IJ and IH = 0.75. Find HJ
we have that
H is between I and J and H is the midpoint of IJ
so
----> because H is the midpoint
we have
therefore
Part 4) H is the midpoint of IJ and IJ = 9.4. Find IH
we have that
H is between I and J and H is the midpoint of IJ
so
-----> equation A
----> equation B
substitute equation B in equation A
substitute the given value and solve for IH
Divide by 2 both sides
Answer:
A. x + 100x/y
Step-by-step explanation:
Machine A= x hours longer to produce 660 widget than machine B
Machine B produces y% more widget per hour than machine A
let
b = Number of hours it takes Machine B to make 660 widgets.
Time taken for Machine A to make the 660 widgets = x + b.
Rate of Machine B = 660/b
Rate of Machine A = 660 / (x + b).
Machine B produces y% more widgets per hour than Machine A:
660 / (x + b)(1 + y/100) = 660/b
1 / (x + b)(1 + y/100) = 1 / b
Multiply both sides by (x+b)
1 + y/100 = (x + b)/b
1 + y/100 = x/b + 1
Subtract 1 from both sides
y/100 = x/b
Take the inverse of both sides
100/y = b/x
Make b the subject
100x/y = b
b=100x/y
The time taken for Machine A to make the 660 widgets is x + b = x + 100x/y.
Answer is A. x + 100x/y