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KATRIN_1 [288]
3 years ago
14

Water flowed out of a tank at a steady rate. A total of 18 1/2 gallons flowed out of the tank in 4 1/4 hours. Which expression

Mathematics
2 answers:
Alecsey [184]3 years ago
6 0

Answer:

In 1 hour water flowed out = \frac{74}{17}  gallons

Step-by-step explanation:

Given as ,

The quantity of water flowed out of tank =  18 \frac{1}{2} gallons

                                                                   =    \frac{37}{2} gallons

The time spend in flowing water out of tank = 4  \frac{1}{4} hours

                                                                          =    \frac{17}{4} hours

∵ In  \frac{17}{4} hours , water flowed out =  \frac{37}{2}

∴ In    1    hours                           ,  water flowed out = \frac{37\times4}          {17\times2}

So, in 1 hour water flowed out = \frac{74}{17}  gallons Answer

Lerok [7]3 years ago
4 0

Answer:

The tank flowed out 4\frac{6}{17} gallons per hour.

Step-by-step explanation:

We know that

The tank flowed out 18\frac{1}{2} gallons in 4\frac{1}{4} hours.

To find the ratio of change, that is, the number of gallons per hour, we just need to divide these quantities as follows

18\frac{1}{2} \div 4\frac{1}{4}=\frac{37}{2}\div \frac{17}{4}=\frac{37}{2}\times \frac{4}{17}=\frac{148}{34}=\frac{74}{17} =4\frac{6}{17}

<h2>Therefore, </h2>

the tank flowed out 4\frac{6}{17} gallons per hour.

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Use the circle to solve for the missing measures. Assume lines that appear tangent are tangent. Do NOT round any answers.
wlad13 [49]

The given circle having two external tangents, according to circle

theorem, have the following values;

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r² + 1.6² = (0.4 + r)²

(0.4 + r)² - (r² + 1.6²) = 0

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m∠2 = (360 - (82 + 98 + 82)) ÷ 2 = 49°

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