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eduard
3 years ago
12

hey anyone here! I need some help solving and understanding these please! I tried so hard but don't quite understand

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
3 0

Step-by-step explanation:

this is the solution to both of these questions in that picture.

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Find the area enclosed by the graphs of x + y = 6 , x − y = 0 , y + 5x = 6 .
LekaFEV [45]
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6 0
3 years ago
Suppose that a standardized biology exam has a mean score of 80% correct, with a standard deviation of 3. The school administrat
NemiM [27]

Answer:

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

A sample of 65 students from the freshmen class is used and a mean score of 76% correct is obtained.

This means that n = 65, \pi = 0.76

99% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 - 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.6236

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 + 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.8964

0.6236*100 = 62.36%

0.8964*100 = 89.64%

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

6 0
3 years ago
Is someone able to help me with this please I don't understand.
gulaghasi [49]

Answer:

d

Step-by-step explanation: if you pay attention to this answer its for points thanks

6 0
2 years ago
If x = 8 and n = 3, Evaluate the following expression: 3x - 3n + 2
Firlakuza [10]

Answer:

7

Step-by-step explanation:

3x8-3x3+2

24-3x3+2

24-9+2

15+2

=17

5 0
3 years ago
PLEASE HELP!!!!!!!!
vfiekz [6]

Answer:

about 78 years

Step-by-step explanation:

Population

y =ab^t  where a is the initial population and b is 1+the percent of increase  

    t is in years

y = 2000000(1+.04)^t

y = 2000000(1.04)^t

Food

y = a+bt   where a is the initial population and b is constant increase

    t is in years

b = .5 million = 500000

y = 4000000 +500000t

We need to set these equal and solve for t to determine when food shortage will occur

2000000(1.04)^t= 4000000 +500000t

Using graphing technology, (see attached graph  The y axis is in millions of years), where these two lines intersect is the year where food shortages start.

t≈78 years

8 0
3 years ago
Read 2 more answers
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