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3 years ago

Please help ill give brainliest!!! Others get 5 stars and a thank you

Mathematics

1 answer:

grandymaker [24]3 years ago

5 0

Answer:

I think the answer is 32cm²

Step-by-step explanation:

A lot of mathematics using a calculator and checking all possible answers led me to this possible solution.

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The sum of three consecutive integers is -30. find the integers.

slega [8]

Consecutive integers are one apart from each tother
they are
x,x+1,x+2

sum is -30
x+x+1+x+2=-30
3x+3=-30
minus 3 both sides
3x=-33
divide 3
x=-11

find rest
x+1=-11+1=-10
x+2=-11+2=-9

they are
-9,-10,-11

5 0

3 years ago

What is the value of x x=2.25 X= 11.25 x= 13 x= 22

Gemiola [76]

we know that

The sum of the internal angles of a triangle must be equal to $180$ degrees

see the attached figure with letters to better understand the problem

m∠B+ $(6x+1)=180$ °-----> by supplementary angles

m∠B= $179-6x$

m∠A= $2x+10$

m∠C= $79$

m∠A+m∠B+m∠C= $180$

Substitute

$(2x+10)+(179-6x)+79=180\\ -4x+268=180\\ 4x=268-180\\ 4x=88\\ x=22\ degrees$

therefore

the answer is

the value of x is equal to $22\ degrees$

5 0

3 years ago

Use Simpson's Rule with n = 10 to estimate the arc length of the curve. Compare your answer with the value of the integral produ

SOVA2 [1]

$y=\ln(6+x^3)\implies y'=\dfrac{3x^2}{6+x^3}$

The arc length of the curve is

$\displaystyle\int_0^5\sqrt{1+\frac{9x^4}{(6+x^3)^2}}\,\mathrm dx$

which has a value of about 5.99086.

Let $f(x)=\sqrt{1+\frac{9x^4}{(6+x^3)^2}}$ . Split up the interval of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [9/2, 5]

The left and right endpoints are given respectively by the sequences,

$\ell_i=\dfrac{i-1}2$

$r_i=\dfrac i2$

with $1\le i\le10$ .

These subintervals have midpoints given by

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4$

Over each subinterval, we approximate $f(x)$ with the quadratic polynomial

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

so that the integral we want to find can be estimated as

$\displaystyle\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It turns out that

$\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{f(\ell_i)+4f(m_i)+f(r_i)}6$

so that the arc length is approximately

$\displaystyle\sum_{i=1}^{10}\frac{f(\ell_i)+4f(m_i)+f(r_i)}6\approx5.99086$

5 0

3 years ago

At the start of the day there was 129.75 in the till one hour later there is 145.40 how much did the shop take in a hour

777dan777 [17]

At the start of the day, there was £129.75. Later, they made more money, so the £145.50. To find the amount of change, you just need to deduct the number 129.75 from 145.50.

145.50 - 129.75 = 15.75

The shop made £15.75 in one hour.

8 0

3 years ago

You are the crew chief of the Algebra 2 formula racing team. Your current tasla is to determine fuel consumption of both cars. C

noname [10]

Answer:

Step-by-step explanation:

5 0

3 years ago