Option A. All the real values of x where x < -1
Procedure
Solve the inequality:
(x -3)(x+1)>0
That happens in two cases.
1) When both factors >0
x-3>0 and x+1>0
x>3 and x >-1
The intersection is x >3
2) When both factors <0
x-3<0 and x+1<0
x<3 and x<-1
the intersection is x<-1.
We have obtained that the function is positive for the intervals x < -1 and x > 3. But in one of those intervals the function is decresing and in the other is increasing.
You can recognize that the function given is a parabola and, because the coefficient of the quadratic term is positive, the parabola opens upward. Then the function is decreasing in the first interval and increasing in the second interval.
3n+4=-5
do the opposite of adding 4. this means you have to subtract 4 from 4. whatever you do to the problem, you must do to the answer. now subtract 4 from -5.
-5-4=-9
since 4-4=0, we can take 4 out of the equation. now you have:
3n=-9
now divide -9 by 3
-9/3=-3
n=-3
hope this helps :)
Answer:
m∠HMO=102°
Step-by-step explanation:
we know that
In a Rhombus the diagonals bisect the angles and opposite angles are equal
In this problem
Angles HMO and HTO are opposite angles
m∠HMO=m∠HTO
m∠HTM=(1/2)m∠HMO ----> because the diagonals bisect the angles and opposite angles are congruent
substitute the values
solve for x
<em>Find the measure of angle HMO</em>
m∠HMO=(12x-6)°
substitute the value of x
m∠HMO=(12(9)-6)=102°
see the attached figure to better understand the problem
