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Snezhnost [94]
3 years ago
13

Use the histograms to answer the question.

Mathematics
1 answer:
Snezhnost [94]3 years ago
7 0
The answer is 12 lokk at the adult is 15 tennagerrs 27 27-15=12
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The difference between a number and 8 is 11
quester [9]

Answer:

The difference between 19 and 8 is 11.

Step-by-step explanation:

Given:

The difference between a number and 8 is 11

Find the number.

Solution:

Let the unknown number be =x

The difference between the unknown number can be written as:

x-8

We are given that the difference =11

So we can write the equation to find x as :

x-8=11

Using additive property to solve for x

Adding 8 to both sides to isolate x on one side.

x-8+8=11+8

∴ x=19

∴ The unknown number = 19

6 0
3 years ago
Read 2 more answers
a ramp measures 6 feet long. if the ramp is 12 inches tall, what is the horizontal distance it covers? i'll give brainliest to w
luda_lava [24]

we know that

1 ft--------> is equals to 12 in

the ramp is 12 inches tall----------> 1 ft tall

A ramp measures------------------>  6 ft long

applying the Pythagorean theorem

c²=a²+b²

where

c-----> 6 ft long

a----> horizontal distance

b-----> 1 ft tall

a²=c²-b²------> a²=6²-1²-----> a²=35------> a=√35------> a=5.92 ft

the answer is

5.92 ft

6 0
2 years ago
Read 2 more answers
the length of a rectangle is 12 inches more than it's width what is it's width of the rectangle if the perimeter is 42 inches​
dimaraw [331]

Answer:

3.5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
For the straight line defined by the points (3, 59) and (5, 87), determine the slope and y-intercept. do not round the answers.
Margarita [4]
(3,59)(5,87)
slope = (87 - 59) / (5 - 3) = 28/2 = 14 <== ur slope

y = mx + b
slope(m) = 14
use either of ur points...(3,59)...x = 3 and y = 59
now we sub and find b, the y int
59 = 14(3) + b
59 = 42 + b
59 - 42 = b
17 = b <=== ur y int (0,17)
4 0
3 years ago
1. Let a; b; c; d; n belong to Z with n &gt; 0. Suppose a congruent b (mod n) and c congruent d (mod n). Use the definition
lukranit [14]

Answer:

Proofs are in the explantion.

Step-by-step explanation:

We are given the following:

1) a \equi b (mod n) \rightarrow a-b=kn for integer k.

1) c \equi  d (mod n) \rightarrow c-d=mn for integer m.

a)

Proof:

We want to show a+c \equiv b+d (mod n).

So we have the two equations:

a-b=kn and c-d=mn and we want to show for some integer r that we have

(a+c)-(b+d)=rn. If we do that we would have shown that a+c \equiv b+d (mod n).

kn+mn   =  (a-b)+(c-d)

(k+m)n   =   a-b+ c-d

(k+m)n   =   (a+c)+(-b-d)

(k+m)n  =    (a+c)-(b+d)

k+m is is just an integer

So we found integer r such that (a+c)-(b+d)=rn.

Therefore, a+c \equiv b+d (mod n).

//

b) Proof:

We want to show ac \equiv bd (mod n).

So we have the two equations:

a-b=kn and c-d=mn and we want to show for some integer r that we have

(ac)-(bd)=tn. If we do that we would have shown that ac \equiv bd (mod n).

If a-b=kn, then a=b+kn.

If c-d=mn, then c=d+mn.

ac-bd  =  (b+kn)(d+mn)-bd

          =    bd+bmn+dkn+kmn^2-bd

          =           bmn+dkn+kmn^2

          =            n(bm+dk+kmn)

So the integer t such that (ac)-(bd)=tn is bm+dk+kmn.  

Therefore, ac \equiv bd (mod n).

//

3 0
3 years ago
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