Answer:
The Proof for
Part C , Qs 9 and Qs 10 is below.
Step-by-step explanation:
PART C .
Given:
AD || BC ,
AE ≅ EC
To Prove:
ΔAED ≅ ΔCEB
Proof:
Statement Reason
1. AD || BC 1. Given
2. ∠A ≅ ∠C 2. Alternate Angles Theorem as AD || BC
3. ∠AED ≅ ∠CEB 3. Vertical Opposite Angle Theorem.
4. AE ≅ EC 4. Given
5. ΔAED ≅ ΔCEB 5. By A-S-A congruence test....Proved
Qs 9)
Given:
AB ≅ BC ,
∠ABD ≅ ∠CBD
To Prove:
∠A ≅ ∠C
Proof:
Statement Reason
1. AB ≅ BC 1. Given
2. ∠ABD ≅ ∠CBD 2. Given
3. BD ≅ BD 3. Reflexive Property
4. ΔABD ≅ ΔCBD 4. By S-A-S congruence test
5. ∠A ≅ ∠C 5. Corresponding parts of congruent Triangles Proved.
Qs 10)
Given:
∠MCI ≅ ∠AIC
MC ≅ AI
To Prove:
ΔMCI ≅ ΔAIC
Proof:
Statement Reason
1. ∠MCI ≅ ∠AIC 1. Given
2. MC ≅ AI 2. Given
3. CI ≅ CI 3. Reflexive Property
4. ΔMCI ≅ ΔAIC 4. By S-A-S congruence test
Step 1: x²-15=2x
step 2: x²-2x-15=0
step 3: (x-5)(x+3)=0
step 4: x-5=0 or x+3=0
step 5: x=5 of x=-3
Answer:
So the probability of drawing a second red marble is 8 out 10 or 0.8.
Step-by-step explanation:
It seems to me that if one red marble is already gone, there are 8 red marbles left out of a total of 10 marbles.
So the probability of drawing a second red marble is 8 out 10 or 0.8.
Perpendicular = opposite sign and reciprocal slope
Slope 2 turns into -1/2
Y = -1/2x + b
Plug in the point
-5 = -1/2(2) + b, b = -4
Solution: y = -1/2x - 4
