Answer:
f(6) = 24
Step-by-step explanation:
f(x) = x^2 - 2x
Let x = 6
f(6) = 6^2 - 2(6)
= 36 - 12
= 24
Answer:
about 9.4 units
Step-by-step explanation:
Distance formula:
√(x1 - x2)² + (y2 - y1)²
Coordinates:
A (4, 2)
B (9, 10)
Let's make 9 = x1
Let's make 4 = x2
Let's make 10 = y1
Let's make 2 = y2
Substitute into the distance formula:
√(x1 - x2)² + (y2 - y1)²
√(9 - 4)² + (2 - 10)²
Solve:
√(9 - 4)² + (2 - 10)²
√(5)² + (-8)²
√25 + 64
√89
≈ 9.4
Therefore, the length of AB is approximately 9.4 units.
Answer:
From -2<x<-1, the function F(X) is increasing. (B)
Really, it increases all from around -2.5<x<0.5
C is also the second answer, as it increases til around 2.5
It is decreasing from -4<x<-3. But increases right after. It then starts to slow down around x = 1 and go down again.
Which means (B) is your answer.
If you want to get fancy, its a polynomial and if you take the derivative for instantaneous rate, you will see f prime is increasing if you make an example function.
Answer:
<em>The voltage at the middle source is</em> 
Step-by-step explanation:
<u>Voltage Sources in Series</u>
When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.
The figure shown has three voltage sources of values:



The sum of these voltages is:

Operating:

We know the total voltage is
, thus:

Equating the real parts and the imaginary parts independently:
4+a=6
1+b=-3
Solving each equation:
a = 2
b = -4
The voltage at the middle source is 
You can verify the zeros of the function y=x2+6x-7 by using a graph and finding where the graph C. <span>C. crosses the x-axis . Finding the zeros mean equating the equation to 0 or y =0. When y =0, this is equal to x-axis. C. is the answer to the problem given above. </span>