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3 years ago

If I have 20 dollars then i buy 13 dollars worth of food how much dollars do i have .

Mathematics

2 answers:

Sophie [7]3 years ago

5 0

Answer:

u have 7$

Step-by-step explanation:

victus00 [196]3 years ago

4 0

Answer: 7

Step-by-step explanation:

you need to answer the question like this:

20-13= 7

that is the answer because, you originally have $20, you send those $13 so you would only have 7 dollars left.

Good luck on your work!

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3 years ago

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Find the equation of a line parallel to −4x−5y=−4 that contains the point (3,−2). Write the equation in slope-intercept form.

Temka [501]

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange - 4x - 5y = - 4 into this form

Add 4x to both sides

- 5y = 4x - 4 ( divide all terms by - 5 )

y = - $\frac{4}{5}$ + $\frac{4}{5}$ ← in slope- intercept form

with slope m = - $\frac{4}{5}$

Parallel lines have equal slopes, thus

y = - $\frac{4}{5}$ x + c ← is the partial equation

To find c substitute (3, - 2) into the partial equation

- 2 = - $\frac{12}{5}$ + c ⇒ c = - 2 + $\frac{12}{5}$ = $\frac{2}{5}$

y = - $\frac{4}{5}$ x + $\frac{2}{5}$ ← in slope- intercept form

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4 years ago

Andre types 208 words in 4 minutes. Noah types 342 words and 6 minutes.who types faster explain?

Vanyuwa [196]

Answer:

Noah

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Find how many words each person types in one minute. Andre types 208/4=52 words/min and Noah types 342/6=57 words/min. The answer is Noah.

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If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ? sin Θ = square root 2 ov

densk [106]

Answer:

$\huge\boxed{\sin\theta=-\dfrac{\sqrt2}{2};\ \tan\theta=-1}$

Step-by-step explanation:

We have:

$\\cos\theta=\dfrac{\sqrt2}{2},\ \dfrac{3\pi}{2}$

For sine use:

$\sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x$

Substitute:

$\sin^2\theta=1-\left(\dfrac{\sqrt2}{2}\right)^2\\\\\sin^2\theta=1-\dfrac{(\sqrt2)^2}{2^2}\\\\\sin^2\theta=1-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4}{4}-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4-2}{4}\\\\\sin^2\theta=\dfrac{2}{4}\to\sin\theta=\pm\sqrt{\dfrac{2}{4}}\\\\\sin\theta=\pm\dfrac{\sqrt2}{\sqrt4}\\\\\sin\theta=\pm\dfrac{\sqrt2}{2}$