Answer:
0.85% probability that the first two are good and the last three are spoiled
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
The order in which the first two jugs is not important, as is not the order in which the last three are selected. So we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
Desired outcomes:
2 spoiled, from a set of 43-11 = 32.
3 spoiled, from a set of 11.
So
Total outcomes:
5 jugs from a set of 43.
Probability:
0.85% probability that the first two are good and the last three are spoiled
Yes, because if you divide 9/.75 you get 12 which means 12 toppings can be added evenly on the pizza
34% of the scores lie between 433 and 523.
Solution:
Given data:
Mean (μ) = 433
Standard deviation (σ) = 90
<u>Empirical rule to determine the percent:</u>
(1) About 68% of all the values lie within 1 standard deviation of the mean.
(2) About 95% of all the values lie within 2 standard deviations of the mean.
(3) About 99.7% of all the values lie within 3 standard deviations of the mean.
Z lies between o and 1.
P(433 < x < 523) = P(0 < Z < 1)
μ = 433 and μ + σ = 433 + 90 = 523
Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.
i. e. 
Here μ to μ + σ = 
Hence 34% of the scores lie between 433 and 523.
Answer:
put a more clear pic
Step-by-step explanation:
