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Zanzabum
2 years ago
6

A baseball is thrown straight up in the air with an initial velocity of 2 m/s. Draw a picture that shows the path of the ball as

it goes up and comes down. Label the initial velocity, the velocity at max. height, and the acceleration of the ball.
Mathematics
1 answer:
adoni [48]2 years ago
6 0

Answer:

e

Step-by-step explanation:

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Evaluate the expression:<br> 3(a + b - 3) - 212a + b - 4) when a = 2 and b = 1
olga_2 [115]

Answer:

417

Step-by-step explanation:

3(2+1-3)-212*2+1-4=?

3-212*2+1-4=?

3-423+1-4=?

420+1-4=?

421-4=?

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Can someone be my friend and solve 5x(x+4)
kvasek [131]

Answer:

5x^2 + 20x

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3 years ago
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Find the equation of the line through the points (-9,6) and (1,27).
bulgar [2K]

The equation of a line in the slope intercept form is expressed as

y = mx + c

where

m represents slope

c represents y intercept

The formula for calculating slope is expressed as

m = (y2 - y1)/(x2 - x1)

From the information given, the line passes through an initial point of (- 9, 6) and (1, 27). This means that

x1 = - 9, y1 = 6

x2 = 1, y2 = 27

By substituting these values into the slope formula, we have

m = (27 - 6)/(1 - - 9) = 21/(1 + 9) = 21/10

We would find the y intercept by substituting m = 21/10, x = - 9 and y = 6 into the slope intercept equation. We have

6 = 21/10 * - 9 + c = - 189/10 + c

c = 6 + 189/10 = 249/10

By substituting m = 21/10 and c = 249/10 into the slope intercept equation, the equation of the line is

y = 21x/10 + 249/10

In decimal form, the equation of the line is

y = 2.1x + 24.9

3 0
1 year ago
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What is the solution to this system of linear equations? 12q+3r=15 -4q-4r=-44
PIT_PIT [208]
12q+3r=15
-4q-4r=-44
-4q=-44+4r
q=11-r
12(11-r)+3r=15
132-12r+3r=15
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117=9r
r=13
-4q-4(13)=-44
-4q-52=-44
-4q=8
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3 years ago
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