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Aneli [31]
3 years ago
15

HELPPP MEE PEOPLE PLSSS NO BOTS OR I WILL REPORT BUT PLEASEEE HELPPP MEEE Find the point-slope equation of the line using the po

int (7,4) and slope of 3/2
Use the slash key ( / ) to indicate a fraction.

Mathematics
2 answers:
rusak2 [61]3 years ago
3 0

Equation: y = 3/2x - 6 1/2, or y = 1.5 - 6.5

If this line is given to have a slope of 3/2, let us at least put it in standard form, substituting the point ( 7, 4 ) into the equation afterwards:

y = 3/2* x + b, provided b ⇒ y - intercept,

( 4 ) = 3/2 * ( 7 ) + b,

4 = 21/2 + b,

b = 4 - 10.5,

b = -6.5

Equation: y = 3/2x - 6 1/2, or y = 1.5 - 6.5

Soloha48 [4]3 years ago
3 0

Answer:

Equation: y = 3/2x - 6 1/2, or y = 1.5 - 6.5

If this line is given to have a slope of 3/2, let us at least put it in standard form, substituting the point ( 7, 4 ) into the equation afterwards:

y = 3/2* x + b, provided b ⇒ y - intercept,

( 4 ) = 3/2 * ( 7 ) + b,

4 = 21/2 + b,

b = 4 - 10.5,

b = -6.5

Equation: y = 3/2x - 6 1/2, or y = 1.5 - 6.5

Step-by-step explanation:

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3 years ago
Which number is additive inverse of -4 1/4
Nadusha1986 [10]

Answer:

4 1/4

Step-by-step explanation:

the additive inverse is a number that when you add it with the number you already had, makes 0

-2 is the additive inverse of 2

so 4 1/4 is the inverse of -4 1/4

7 0
2 years ago
Could someplease explain the whole problem? For the first part my the answer I got was x= .618, -.618, and <img src="https://tex
algol13

9514 1404 393

Answer:

  a) x = (√5 -1)/2 ≈ 0.618034

  b) 1/x = (√5 +1)/2 ≈ 1.618034

Step-by-step explanation:

<u>Given</u>:

  x/(1 -x) = 1/x

<u>Find</u>:

  Exactly, and as a decimal approximation, ...

  a) x, using the quadratic formula

  b) 1/x

<u>Solution</u>:

a) We can multiply the given equation by x(1 -x) to obtain ...

  x² = 1 -x

  x² +x -1 = 0 . . . . . . add x-1

The coefficients for use in the quadratic formula are a=1, b=1, c=-1. The solution using the quadratic formula is ...

  x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-1\pm\sqrt{1^2-4\cdot1\cdot(-1)}}{2\cdot1}=\dfrac{-1\pm\sqrt{5}}{2}

We are only interested in the positive solution, which is ...

  \boxed{x=\dfrac{\sqrt{5}-1}{2}\approx0.618034}

__

b) The quadratic we developed in the first part can be rearranged like this:

  x² +x = 1 . . . . . . add 1 to both sides

  x(x +1) = 1 . . . . . factor out x

  x +1 = 1/x . . . . . .divide by x

Then to find the value of 1/x, we simply need to add 1 to the value of x we have:

  \dfrac{1}{x}=\dfrac{\sqrt{5}-1}{2}+1=\dfrac{\sqrt{5}-1}{2}+\dfrac{2}{2}=\dfrac{\sqrt{5}-1+2}{2}\\\\\boxed{\dfrac{1}{x}=\dfrac{\sqrt{5}+1}{2}\approx1.618034}

5 0
2 years ago
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