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Arlecino [84]
3 years ago
5

What is the range of the function Rx) = 4x + 9, given the domain D = {-4, -2, 0, 2}?

Mathematics
1 answer:
notka56 [123]3 years ago
3 0

Answer:

-7, 1, 9, 17

Step-by-step explanation:

  1. F1=4*4+9=-16+9=-7
  2. F2=4*2+9=-8+9=1
  3. F3=4*0+9=0+9=9
  4. F4=4*2+9=8+9=17
You might be interested in
There are 765 marbles in a box. There are twice as many blue marbles as green marbles. There are three times as many red marbles
Digiron [165]
B=blue
g=green
r=red
2 times as many blue as green
b=2g
3 times as many red as blue
r=3b
subsitute 2g for b
r=3(2g)=6g
r=6g

r+g+b=765
so we subsitute
r=6g
g=g
b=2g

6g+g+2g=765
add like terms
9g=765
divide both sides by 9
g=85
subsitute
b=2b
b=2(85)
b=170

170 blue
5 0
3 years ago
Find the slope of the line going through the points (-1,0) and
pav-90 [236]

Answer:

Slope = -2

Step-by-step explanation:

Slope = \frac{y^{2}-y^{1}  }{x^{2} -x^{1} }

Slope = \frac{-4-0}{1-(-1)}=\frac{-4}{2}=-2

5 0
3 years ago
The episodes of a TV program are each 50 minutes long.
Nimfa-mama [501]

Answer:

3 hours 20 minutes

Step-by-step explanation:

first multiply 50 by how many episodes were watched

50 * 4 = 200

then devide it by 60 (60 minutes in an hr)

200 / 60 = 3 with a remainder of 1/3

meaning that it is 3 1/3 hours, to convert this into minutes, just devide a full hour (60 minutes) by 3

60 / 3 = 20

therefore the answer is 3 hours and 20 minutes

6 0
3 years ago
Evaluate the question
Vesna [10]

Answer:

we conclude that:

\frac{2^{-\frac{4}{3}}}{54^{-\frac{4}{3}}}=81

Step-by-step explanation:

Given the expression

\frac{2^{-\frac{4}{3}}}{54^{-\frac{4}{3}}}

\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}\:=\:x^{a-b}

\frac{2^{-\frac{4}{3}}}{54^{-\frac{4}{3}}}=\left(\frac{2}{54}\right)^{-\frac{4}{3}}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

         =\frac{1}{\left(\frac{2}{54}\right)^{\frac{4}{3}}}

        =\left(\frac{1}{27}\right)^{-\frac{4}{3}}

\mathrm{Apply\:exponent\:rule}:\quad \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c}

        =\frac{1}{\frac{1^{\frac{4}{3}}}{27^{\frac{4}{3}}}}

         =\frac{1}{\frac{1^{\frac{4}{3}}}{81}}      ∵ 27^{\frac{4}{3}}=81

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{1}{\frac{b}{c}}=\frac{c}{b}

         =\frac{81}{1^{\frac{1}{3}}}              

\mathrm{Apply\:rule}\:1^a=1

         =\frac{81}{1}

          =81

Therefore, we conclude that:

\frac{2^{-\frac{4}{3}}}{54^{-\frac{4}{3}}}=81

                         

7 0
3 years ago
6) If sec theta+tan theta = P. PT sin theta=P^2-1/P^2+1 ...?
jarptica [38.1K]
I will use the letter x instead of theta.

Then the problem is, given sec(x) + tan(x) = P, show that

sin(x) = [P^2 - 1] / [P^2 + 1]

I am going to take a non regular path.

First, develop a little the left side of the first equation:

sec(x) + tan(x) = 1 / cos(x) +  sin(x) / cos(x) = [1 + sin(x)] / cos(x)

and that is equal to P.

Second, develop the rigth side of the second equation:

[p^2 - 1] / [p^2 + 1] =

= [ { [1 + sin(x)] / cos(x) }^2 - 1] / [ { [1 + sin(x)] / cos(x)}^2 +1 ] =

=  { [1 + sin(x)]^2 - [cos(x)]^2 } / { [1 + sin(x)]^2 + [cos(x)]^2 } =

= {1 + 2sin(x) + [sin(x)^2] - [cos(x)^2] } / {1 + 2sin(x) + [sin(x)^2] + [cos(x)^2] }

= {2sin(x) + [sin(x)]^2 + [sin(x)]^2 } / { 1 + 2 sin(x) + 1} =

= {2sin(x) + 2 [sin(x)]^2 } / {2 + 2sin(x)} = {2sin(x) ( 1 + sin(x)} / {2(1+sin(x)} =

= sin(x)

Then, working with the first equation, we have proved that [p^2 - 1] / [p^2 + 1] = sin(x), the second equation.


4 0
4 years ago
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