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Arlecino [84]
3 years ago
5

What is the range of the function Rx) = 4x + 9, given the domain D = {-4, -2, 0, 2}?

Mathematics
1 answer:
notka56 [123]3 years ago
3 0

Answer:

-7, 1, 9, 17

Step-by-step explanation:

  1. F1=4*4+9=-16+9=-7
  2. F2=4*2+9=-8+9=1
  3. F3=4*0+9=0+9=9
  4. F4=4*2+9=8+9=17
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3rd choice

Step-by-step explanation:

9/5 = 18/10 = 1.8

All your numbers are between 1 and 2, and all have a fractional part that is a whole number of tenths. 1.3, 1.5, and 1.8 will be correctly shown by dots on the 3rd, 5th, and 8th marks.

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If w=125 then what is 12456+w ?
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12,581

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Three less than one-half a number is –71.
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Answer: -136

Step-by-step explanation:

1/2(x)-3=-71

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3 years ago
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a father is 43 years old and his 2 children is 8 and 6 years old. how many years will the sum of the ages of the two children be
elena55 [62]

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Step-by-step explanation:

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7 0
3 years ago
The circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm. (a) Use differentials to estimate the ma
andreev551 [17]

The maximum error in the calculated surface area is 24.19cm² and the relative error is 0.0132.

Given that the circumference of a sphere is 76cm and error is 0.5cm.

The formula of the surface area of a sphere is A=4πr².

Differentiate both sides with respect to r and get

dA÷dr=2×4πr

dA÷dr=8πr

dA=8πr×dr

The circumference of a sphere is C=2πr.

From above the find the value of r is

r=C÷(2π)

By using the error in circumference relation to error in radius by:

Differentiate both sides with respect to r as

dr÷dr=dC÷(2πdr)

1=dC÷(2πdr)

dr=dC÷(2π)

The maximum error in surface area is simplified as:

Substitute the value of dr in dA as

dA=8πr×(dC÷(2π))

Cancel π from both numerator and denominator and simplify it

dA=4rdC

Substitute the value of r=C÷(2π) in above and get

dA=4dC×(C÷2π)

dA=(2CdC)÷π

Here, C=76cm and dC=0.5cm.

Substitute this in above as

dA=(2×76×0.5)÷π

dA=76÷π

dA=24.19cm².

Find relative error as the relative error is between the value of the Area and the maximum error, therefore:

\begin{aligned}\frac{dA}{A}&=\frac{8\pi rdr}{4\pi r^2}\\ \frac{dA}{A}&=\frac{2dr}{r}\end

As above its found that r=C÷(2π) and r=dC÷(2π).

Substitute this in the above

\begin{aligned}\frac{dA}{A}&=\frac{\frac{2dC}{2\pi}}{\frac{C}{2\pi}}\\ &=\frac{2dC}{C}\\ &=\frac{2\times 0.5}{76}\\ &=0.0132\end

Hence, the maximum error in the calculated surface area with the circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm is 24.19cm² and the relative error is 0.0132.

Learn about relative error from here brainly.com/question/13106593

#SPJ4

3 0
2 years ago
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