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olasank [31]
3 years ago
15

The gas tank in dad’s car holds 12 gallons. The gas tank in mom’s truck holds 50% more than that. How much gas does the truck’s

tank hold?
**18 gallons**
Explain why this situation can be represented by the equation ( 1.5 ) ⋅ 12 = t. Make sure that you explain what t represents.
Mathematics
1 answer:
sweet [91]3 years ago
6 0

Answer:

<h2>Below, Hope this helps :)</h2>

Step-by-step explanation:

The variable t represents the amount of gas in mom's truck. Since we need to find a number that is 50% more than 12, we use 1.5 (we would use 2 if we want 100% more, so it makes sense that we use 1.5, since we want to add 1/2 of 12 to 12. The answer is 18.)

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Rama09 [41]

Answer:

-6.8

Step-by-step explanation:

4 0
3 years ago
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In the graphic above, ΔRED ≅ ΔTAN by: aHL. bSSA. cSAS. dThe triangles are not congruent.
USPshnik [31]

Answer:

a. HL

Step-by-step explanation:

ΔRED ≅ ΔTAN by HL Postulate of congruen.

3 0
3 years ago
What is the maximum number of possible solutions for the system shown below?
julsineya [31]

\bf \begin{cases} 3x^2+y^2=4\\[-0.5em] \hrulefill\\ x^2+y=5\implies \boxed{y}=5-x^2 \end{cases} \\\\\\ \stackrel{\textit{substituting \boxed{y} in the 1st equation}}{3x^2+\left( \boxed{5-x^2} \right)^2=4}\implies 3x^2+25-10x^2+x^4=4 \\\\\\ x^4-8x^2+21=0\impliedby \begin{array}{llll} \textit{the degree of this polynomial}\\ \textit{is 4, and by the fundamental}\\ \textit{theorem of algebra, it can}\\ \textit{have \boxed{4} solutions at most} \end{array}

7 0
4 years ago
Select all triangles whose side lengths prove they are right triangles. You must select all that apply.
Bogdan [553]
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2 years ago
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Please Help? A circle has an arc length of 5π in. The central angle for this arc measures π/3 radians. What is the area of the a
Zielflug [23.3K]

Answer:

The area of the associated sector is \frac{25}{24}\pi \ in^{2}  

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The circumference of a circle is equal to

C=2\pi r

we have

C=5\pi\ in

substitute and solve for r

5\pi=2\pi r

r=2.5\ in

step 2

Find the area of the circle

we know that

The area of the circle is equal to

A=\pi r^{2}

we have

r=2.5\ in

substitute

A=\pi (2.5^{2})=6.25\pi\ in^{2}

step 3

Find the area of the associated sector

we know that

2\pi\ radians subtends the complete circle of area 6.25\pi\ in^{2}

so

by proportion

Find the area of a sector with a central angle of \pi/3\ radians

\frac{6.25\pi }{2\pi} =\frac{x}{\pi/3}\\x=6.25*(\pi/3)/2\\ \\x=\frac{25}{24}\pi \ in^{2}

8 0
4 years ago
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