Answer:
Step-by-step explanation:
Answer:
3.47 and 3.21
Step-by-step explanation:
Let us assume the nails length be X
Value let separated the top 3% is T and for bottom it would be B
Now converting, we get
Based on the normal standard tables, we get
Now compare these two above equations
So for top 3% it is 3.47
Now for bottom we applied the same method as shown above
Based on the normal standard tables, we get
Now compare these two above equations
hence, for bottom it would be 3.21
Answer:
(a) ¬(p→¬q)
(b) ¬p→q
(c) ¬((p→q)→¬(q→p))
Step-by-step explanation
taking into account the truth table for the conditional connective:
<u>p | q | p→q </u>
T | T | T
T | F | F
F | T | T
F | F | T
(a) and (b) can be seen from truth tables:
for (a) <u>p∧q</u>:
<u>p | q | ¬q | p→¬q | ¬(p→¬q) | p∧q</u>
T | T | F | F | T | T
T | F | T | T | F | F
F | T | F | T | F | F
F | F | T | T | F | F
As they have the same truth table, they are equivalent.
In a similar manner, for (b) p∨q:
<u>p | q | ¬p | ¬p→q | p∨q</u>
T | T | F | T | T
T | F | F | T | T
F | T | T | T | T
F | F | T | F | F
again, the truth tables are the same.
For (c)p↔q, we have to remember that p ↔ q can be written as (p→q)∧(q→p). By replacing p with (p→q) and q with (q→p) in the answer for part (a) we can change the ∧ connector to an equivalent using ¬ and →. Doing this we get ¬((p→q)→¬(q→p))
Answer:
option 2 is correct given diagrm
Simple, first we add the numbers up. 3+3+3+3=12, you asked what is the probability that it is a bag of peanuts, their are 3 bags of peanuts. Let's make a fraction. The fraction is going to be 3/12, we can simplify 3/12 into 1/4. So, the answer is A. 1/4
