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Anettt [7]
3 years ago
11

PLEASE HELP FASTT!!!!!!!!!!!!!!!!!!!!!!Determine whether each ratio is equivalent to 1/2,3/9, or 5/7.

Mathematics
1 answer:
torisob [31]3 years ago
4 0
1/2- 3/6 5/10 50/100
3/9- 2/6 1/3
5/7- 10/14 20/28
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A plane flies 440 miles with wind, and 340 miles against wind in same time. If speed of wind is 25 mph, find speed in still air?
Viefleur [7K]
V = s/t

now, t is equal for both cases so we write these 2 equations:
440/(Vp+Vw) = t

and 

340/(Vp-Vw) = t
Now again, since t is equal for both cases we can make these 2 equations equal to eachother.
440/(Vp+25) = 340/(Vp-25)
(Vp - 25)*44=34*(Vp+25)
44Vp - 1100 = 34Vp + 850
10Vp = 1950
Vp = 195

Answer is 195mph
6 0
3 years ago
Cool Scoops ice cream shop offers 60 different one-topping sundaes. If there are 12 flavors of ice cream, how many toppings are
kow [346]
The answer would be 5. 
You have to multiply the two variable which would be the amount of ice cream flavors and the number of toppings to get the amount which is 60. Since we don't know the number of toppings, we divide the whole amount (60) by the variable we do know (types of ice cream; 12) and we get 5. 
7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=128%5E3%2B272%5E3%20%2F128%5E2-128%2A272%2B272%5E2" id="TexFormula1" title="128^3+272^3 /128^2
Sholpan [36]

wait do you want it step by step or just the answer?

the answer is 400

7 0
3 years ago
ABCD IS A TRAPEZIUM <br><br> WORK OUT THE SIZE OF ANGLE CDA.
zvonat [6]

Answer:

The measure of angle CDA is 27.6\°

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle ABF

Applying Pythagoras Theorem

A.F^{2}=6.5^{2}-6^{2}

A.F^{2}=6.25

A.F=2.5\ cm

In the right triangle CED

CE=6\ cm

ED=23-(9+2.5)=11.5\ cm

so

tan(

substitute the values

tan(

(

7 0
3 years ago
Two cars are travelling from Toronto to Quebec. Car A left Toronto at 8 a.m. and is moving with an average speed of 70 km/h. Car
vodka [1.7K]

Answer:

It'll take 7 hours for the car B to cath up to A

Step-by-step explanation:

In order to solve this problem we can write the equation from the distance of each car. Assuming that t = 0 happens when the second car leaves Toronto. When the second car leaves Toronto, the first one is on the road for two hours already, thefeore it travelled a total of:

distance = speed*time = 70*2 = 140

We have:

Car A:

x(t) = 70*t + 140

Car B:

x(t) = 90*t

We now need to find the value of "t" that makes x(t) the same for both cars:

90*t = 70*t + 140

20*t = 140

t = 140 / 20 = 7 h

7 0
3 years ago
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