YS = 2/3 × ( YV ) *.&.* SV = 1/3 × ( YV )
_____________________________
YS = 2/3 × ( YV )
4x + 14 = 2/3 × ( YV )
Multiply both sides by 3/2
( 4x + 14 ) × 3/2 = ( YV ) × 2/3 × 3/2
YV = 6x + 21 ( ☆ )
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SV = 1/3 × ( YV )
1 + 3x = 1/3 × ( YV )
Multiply both sides by 3
( 1 + 3x ) × 3 = ( YV ) × 1/3 × 3
YV = 9x + 3 ( ♡ )
_____________________________
YV = YV
( ☆ ) = ( ♡ )
6x + 21 = 9x + 3
Subtract both sides 3
6x + 21 - 3 = 9x + 3 - 3
6x + 18 = 9x
Subtract both sides 6x
6x - 6x + 18 = 9x - 6x
18 = 3x
Divide both sides by 3
18 ÷ 3 = 3x ÷ 3
x = 6
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YV = 6x + 21 = 9x + 3
YV = 6(6) + 21 = 9(6) + 3
YV = 57
Answer:
This is a right triangle, so we know that:
h² = b' · c'
which is this case can be specificly written as:
BD² = AD · CD
BD² = 7 · 3 = 21
BD = √21
Now that we can also notice that ΔADB is also a right triangle, therefore we can apply the pythagorean theorem:
AD² + BD² = AB²
7² + (√21)² = x²
x² = 49 + 21 = 70
x = √70
Answer:5n+10d=365.7 pennies
Step-by-step explanation:
Answer:
8.25
Step-by-step explanation:
I dont know the weight of the chips but ill answer
ill just round a random number then if thats ok with you