A(b)+16 = 16 larger than the product of a and b.
Answer:
s = -4 ± √31
Step-by-step explanation:
Given 4
+ 32s = 60
divide by 4 throughout


s = -4 ± √31
ANSWER

EXPLANATION
The area of the two tra-pezoidal faces

The area of the 5 by 6.4 rectangular face

The area of the two square faces

The area of the 9 by 5 rectangular face is

The surface area of the design is:
