Answer:
-1
Step-by-step explanation:
-3-2=-5
4-(-1)=5
-5/5 simplifies to -1
This is a neat little question. I don't think I've seen it before.
Step one
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Find c
3^2 + 4^2 = c^2
9 + 16 = c^2
c^2 = 25
c = 5
Step 2
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Set up your first equation for b^2
a^2 + 4^2 = b^2 from triangle XWY
Step 3
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Set up your second equation for b^2
25 +b^2 = (a + 3)^2 from triangle XWZ
Step 4
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Put the results of Step 2 into step 3 and solve
25 + a^2 + 16 = (a + 3)^2 Collect the like terms on the left.
41 + a^2 = (a + 3)^2 Expand the brackets on the right
41 + a^2 = a^2 + 6a + 9 Transfer the 9 to the left.
32 + a^2 = a^2 + 6a Subtract a^2 from both sides.
6a = 32 Divide by 6
a = 32 / 6
a = 5 2/6
a = 5 1/3
Answer:
M=3*2
M=6
Step-by-step explanation:
Well i think you might be missing something, there is no numbers
Given:
1st map = 8 cm
2nd map = 6 cm
1 cm in the map is equal to 2 km on the actual trail.
8 cm * 2km/1cm = 16 km is the actual length of the trail in the first map
6 cm * 2km/1cm = 12 km is the actual length of the trail in the second map.
I'm not sure on how to get the scale factor from the map to the actual trail. I'm confused if I had to consider cm and km because 1km is equal to 100,000 cm.
Proportion of the second map to the first map is 6/8
6/8 = x/3 → 6*3 = 8x → 18/8 = x → 2.25
6/8 = x/4 → 6*4 = 8x → 24/8 = x → 3
6/8 = x/5 → 6*5 = 8x → 30/8 = x →3.75
The side measure of the triangle in the second map is only 75% of the side measure of the triangle in the first map.
