_x + 7 = 10 its x over two 2 X =

Mathematics

1 answer:

Arisa [49]3 years ago

8 0

Answer:

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Step-by-step explanation:

give brainliest or vanish

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-4 1/2 x -3 3/4 <br> Does anyone know how to get the answer to that

taurus [48]

Hello there! Given the equation, we can solve through a series of steps:

1. Convert

In this step, we convert the mixed numbers to make them improper:

2 x 4 + 1 = 9, which means -4 1/2 = -9/2

4 x 3 + 3 = 15, which means -3 3/4 = -15/4

2. Multiply

Now that we have the improper fractions, we can multiply accordingly:

(-9/2 • -15/4) = -135/8

3. Simplify

Since we have our result, we can simplify to a mixed number:

-135/8 = 16 7/8

Your final answer is 16 7/8. Hope this helps!

8 0

2 years ago

PLEASE HELP ME!!! needing help now!

Phoenix [80]

The answer is it should be behind the 7 because you only moved one time in 1.7

7 0

3 years ago

When 9 2/3 is written in simplest radical form, which value remains under the radical?

Vera_Pavlovna [14]

Answer:

The value under the radical is 3

Step-by-step explanation:

9^(2/3) This means 9 squared then find find the cube root of the answer.

9^(2/3)=∛(9^2 )

= ∛81

= ∛(3×3×3×3) = ∛(3)³ ₓ ∛3

= 3∛3

The value under the radical is 3

I hope this now shows clearly the number under the radical is 3.

BRAINLIEST?

3 0

2 years ago

Find sin(a+b) if tan(a)=7/24 where a is in the third quadrant

ludmilkaskok [199]

The complete question in the attached figure

we have that
tan a=7/24 a----> III quadrant
cos b=-12/13 b----> II quadrant
sin (a+b)=?

we know that
sin(a + b) = sin(a)cos(b) + cos(a)sin(b<span>)
</span>
step 1
find sin b
sin²b+cos²b=1------> sin²b=1-cos²b----> 1-(144/169)---> 25/169
sin b=5/13------> is positive because b belong to the II quadrant

step 2
Find sin a and cos a
tan a=7/24
tan a=sin a /cos a-------> sin a=tan a*cos a-----> sin a=(7/24)*cos a
sin a=(7/24)*cos a------> sin²a=(49/576)*cos²a-----> equation 1
sin²a=1-cos²a------> equation 2
equals 1 and 2
(49/576)*cos²a=1-cos²a---> cos²a*[1+(49/576)]=1----> cos²a*[625/576]=1
cos²a=576/625------> cos a=-24/25----> is negative because a belong to III quadrant
cos a=-24/25
sin²a=1-cos²a-----> 1-(576/625)----> sin²a=49/625
sin a=-7/25-----> is negative because a belong to III quadrant

step 3
find sin (a+b)
sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
sin a=-7/25
cos a=-24/25
sin b=5/13
cos b=-12/13
so
sin (a+b)=[-7/25]*[-12/13]+[-24/25]*[5/13]----> [84/325]+[-120/325]
sin (a+b)=-36/325

the answer is
sin (a+b)=-36/325