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3 years ago

HELPP ME PLSSSS NO BOTS OR I WILL REPORT YOUU!!

Mathematics

1 answer:

BigorU [14]3 years ago

5 0

Answer:

True

Step-by-step explanation:

It pases vertical line test but does not have an inverse

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A wax candle is 16 cm long and 1 cm in

mariarad [96]

The correct answer is 149

3 0

4 years ago

A florist sold 12 flower bouqets yesterday, including 2 daisy bouquets. Based on past data, how many of the next 18 boquetes sol

My name is Ann [436]

Answer: 3

Step-by-step explanation:

A florist sold 12 flower bouqets yesterday, which included 2 daisy bouquets. This shows that the fraction of daisy bouquet is 2/12 = 1/6.

Therefore, if there are 18 boquetes sold, the number that's expected to be daisy bouquets will be:

= 1/6 × 18

= 3

4 0

3 years ago

Durante a distribuição de bombons para seus netos, vovó Cláudia percebeu que, se distribuísse 11

Aleksandr [31]

<span>During the distribution of bonbons to her grandchildren, Grandma Claudia realized that if she distributed 11 chocolates for each of them, 10 candies would remain. In the meantime, distribute 13 chocolates each of his grandchildren, would lack 6. Based on this information, it is CORRECT to state that the difference between the number of candies and the number of grandchildren is A) 90. B) 30. C) -90. D) -30.

Let n=number of candies,
and c=number of grandchildren
The story expressed in modulo gives the two following equations:
then
mod(n,11)=10 (ten left if each given 11).............(1)
mod(n,13)=-6, or
mod(n,13)=7 (7 left if each given 13)

By enumerating (1), we have
10,21,32,43,54,65,76,87,98,109...
=> 8*11+10=98
By enumerating (2), we have
7,20,33,46,59,72,85,98,101...
=> 8*13-6=98
Hence there are 8 grandchildren and 98 candies.

The difference of the number of candies and the number of grandchildren is therefore 98-8=90.

Another way to get the number of grandchildren is
c=(10-(-6))/(13-11)=8

</span>

5 0

3 years ago

Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

3 0

4 years ago

I need help please the question is in the picture.

Basile [38]

Answer:

5x+12=42

x=6

Step-by-step explanation:

8+x+x+2+3x+2=42

5x+12=42

5x=42-12

5x=30

x=6

7 0

3 years ago