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3 years ago

I have alg 2 midterms tomorrow, does anyone know a good site to study?

2 answers:

7 0

Yes the notes you took in class and friends from class as well sites to study from wont help as much and we don't know what part of alg 2 you're on.

Kisachek [45]3 years ago

7 0

Um for me I like to use
- https://www.khanacademy.org/math/<span>algebra2
</span>- www.regentsprep.org/Regents/math/algtrig/math-algtrig.htm
<span>- www.classzone.com › Algebra 2
</span>
Hope this helps (:
❤❤❤Please mark as Brilliant ❤❤❤
- A

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Consider parallelogram WXYZ, where diagonal WY and XZ intersect at point Q. If WQ =8 and ZX = 20, which statement is true?

Alina [70]

Answer:

C) YQ = 8

Step-by-step explanation:

If WQ is 8 and XZ bisects this line, this means that YQ is also 8.

If this answer is correct, please make me Brainliest!

8 0

3 years ago

For the equation below, x is the input and y is the output. y = -4x + 3 If the input is -8, then the output is

KonstantinChe [14]

Answer:

Step-by-step explanation:

If is given the value -8 as it is the input then -->

y = -4(-8) + 3

Negative four times negative 8 is positive 32 so

y= 32 + 3

And 32 plus 3 is 35

7 0

3 years ago

Read 2 more answers

Find the sum of the first 50 positive even integers.

adell [148]

2250
50*(2+100)/2
50*102/2
50*51
2250

7 0

3 years ago

Write the inverse of the function: f (x) = 2x+3

34kurt

Answer:

$y = \frac{x - 3}{2}$

Step-by-step explanation:

To find the inverse of a function, simply 'switch' the x and y's and solve for y. $y = 2x + 3$ becomes $x = 2y + 3$ . Now, solving for y, we get $y = \frac{x - 3}{2}$ .

hope this helped! :)

6 0

2 years ago

Determine the point of intersection of right bisectors in a triangle ∆ with vertices A (-3, 5), B (1, 1) and (−7, −3). Find the

iris [78.8K]

Answer:

Point of intersection (-11/3 , 1/3)

All distances from the vertices are $\frac{10\sqrt{2} }{3}$

Step-by-step explanation:

The vertices of the triangle is A(-3,5) , B (1,1) and C (-7,-3)

We need to find the perpendicular bisector of the triangle first

let's take one side connecting A and B

mid point of A and B = (-1,3)

Slope of the line joining A and B = -1

slope of perpendicular to line joining A and B = 1

equation of line passing through (-1,3) with slope 1

y - 3 = 1(x-(-1))

y -3 = x+1

x-y = -4 ............(1)

similarly

mid point joining B and C = (-3,-1)

slope perpendicular to line joining B and C = -2

Equation of perpendicular bisector of line joining B and C =

y +1 = -2(x +3 )

y+1 = -2x -6

2x+y = -7 ..........(2)

On solving 1 and 2

x= -11/3 , y= 1/3

Distances

From A = $\frac{10\sqrt{2} }{3}$

From B = $\frac{10\sqrt{2} }{3}$

From C = $\frac{10\sqrt{2} }{3}$

7 0

3 years ago