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siniylev [52]
2 years ago
5

Police can estimate the speed of a vehicle before the brakes are applied using the formula 0.75d=(s^2)/(30.25) where s is the sp

eed in miles per hour and d is the length of the vehicle’s skid marks. What was the approximate speed of a vehicle that left a skid mark measuring 150 feet?
A) About 11 miles per hour
B) About 15 miles per hour
C) About 58 miles per hour
D) About 67 miles per hour
Mathematics
1 answer:
Jobisdone [24]2 years ago
7 0
The answer is C.

0.75(150) =   \frac{ s^{2}}{30.25}

112.5 * 30.25 =  s^{2}

3413.125 =  s^{2}

s = 58.422
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In a direct variation, the ratio of y -values to x -values is equal to a constant.
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True

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If the simple interest on $6,000 for 4 years is $1,920, then what is the interest rate?
Vsevolod [243]

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6 0
3 years ago
What is the factorise 3m-6
cupoosta [38]

The answer is:      "  3(m − 2)  "  .

__________________________________

  →  The "factorized version" of the binomial expression, " 3m − 6 " ,  is:

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                →   "  3(m − 2) " .

__________________________________

Explanation:

To solve:

__________________________________

<u>Note</u>:  We are given the expression:  " 3m − 6 " ;

and we are asked to "factorize" this expression.

Note that this expression is a "binomial expression" — which means there are two (2) terms — in this case:   "3m" and "6" .

Since only one (1) of these 2 (two) terms has a variable, and the remaining terms is a "constant" (non-zero integer), write these 2 (two) terms as:

 1)  the coefficient of the variable given in the term shown with a "coefficient" :

       →   that is:  "3"  ;  and:

 2)  the other term:  "6" .

→  With the numbers:  "3 and 6" , we can factor out a "3" ;  

          →  {since:  " 6 ÷ 3 = 2 "} ;

 →   So;  given:  

               " 3m − 6 " ;  

 →   We can "factor out" a "3" ; as follows:

           →   Take the first term:  " 3m " :

                    " 3m  =  3 * m " ;

__________________________________

           →   Take the second term:  "  6 " :

                    "  6 = 3 * (what value?) ;

                 → divide each of this equation by "3" ;

    to isolate the "missing value" on one side of the equation; & to solve for the "missing value" ; as follows:

        →           "  6 / 3 = [ 3 * (what value?) ] / 3  ;

                    →  to get:  " 2  =  "(the missing value)"  ;

    →   So;    "  6 = 3 * (what value?) ;

           →     " 6 = 3 * 2 " .  

           →   Take the second term:  "  6 " :

           →     " 6 = 3 * 2 " .

__________________________________

So:    " 3m − 6 "  =  (3 * m) − (3 * 2) " .  

Factor out a "3" ;  as follows:

__________________________________

    →  " 3m − 6 "  =  (3 * m) − (3 * 2) " ;

                           =   " 3(m − 2)  "

__________________________________

Let us check our answer:

__________________________________

Note the "distributive property of multiplication"  :

__________________________________

        a(b + c) = ab +  ac ;  

        a(b − c) = ab −  ac ;

__________________________________

So:  Take our answer:  " 3(m − 2) " .

__________________________________

" 3(m − 2)  = ?  (3*m)  −  (3*2)  " ??  ;

__________________________________

Let us substitute "4" for "m" ;  in both sides of the equation;

              →  to see if the equation holds true;  i.e. to see if both sides of the equation are equal when:  " m = 4 " ;

__________________________________

 We have:

__________________________________

     →  " 3(m − 2)  = ?  (3*m)  −  (3*2)  " ??  ;

First let us rewrite this equation;  substitute "4" for "m" ; as follows:

     →   " 3(4 − 2)  = ?  (3*4)  −  (3*2)  " ??  ;

__________________________________

And calculate;  to see if each side of the equation is equal ; i.e. to see if the equation holds true; as follows:

     →   " 3(2)  = ?  (12)  −  (6)  " ??  ;

     →   "  6  = ?  (6)  " ??  ;

     →   "  6 = 6 " !  Yes!  The equation holds true!

__________________________________

Hope this answer was helpful!

Best wishes!

__________________________________

8 0
3 years ago
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