15 minutes= 2 problems
75 / 15 = 5
2 x 5 = 10 problems
P(2 or 4) = 2/3
p(multiple of 2) = 1
p(multiple of 3) = 1/3
P(odd prime numbers) = 0
<h3>What are the probabilities?</h3>
Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.
P(2 or 4) = (number of sides that have a value of 2 / total number of sides) + (number of sides that have a value of 2 / total number of sides) = 2/6 + 2/6 = 2/3
p(multiple of 2) = number of sides that are a multiple of 2 / total number of sides
6/6 = 1
p(multiple of 3) = number of sides that are a multiple of 3/ total number of sides
= 2/6 = 1/3
P(odd prime numbers) = number of odd prime numbers / total number of sides = 0
To learn more about probability, please check: brainly.com/question/13234031
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Answer:
The probability that none of these taxpayers will be audited by the IRS is 0.8996 or 89.36%
Step-by-step explanation:
According to given:
Probability of being audited for income less than $50,000 = 6/1000 = 0.006
Therefore,
Probability of not being audited for income less than $50,000 = 1 - 0.006 = 0.994
Similary,
Probability of being audited for income more than $100,000 = 49/1000 = 0.049
Therefore,
Probability of not being audited for income more than $100,000 = 1 - 0.049 = 0.951
Now, for the probability of 2 persons with less $50,000 income and 2 persons with more than $100,000 income, to not being audited, we must multiply the probabilities of not being audited of each of the 4 persons.
Therefore,
Probability that none of them is audited = (0.994)(0.994)(0.951)(0.951)
<u>Probability that none of them is audited = 0.8936 = 89.36%</u>
M = (t+1)/(t-3)
m(t-3) = t+1
mt-3m = t+1
(m-1)t = 3m+1
t = (3m+1)/(m-1)
Slope intercept form is to leave y by itself. ok this is the initial question 3x+4y=5 and we want y by itself. first subtract 3x by both sides. you now have 4y=5-3x, then divide 4 by both sides. y=5-3x/4, this is slope intercept form, if you still need help download the app socratic and photomath.
