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Nookie1986 [14]
3 years ago
12

Answer this question please and thank you

Mathematics
2 answers:
DerKrebs [107]3 years ago
6 0

Answer:

Not a 100% sure but the first one is 0.064

The Second is 1

Third is also 1

Step-by-step explanation:

Angelina_Jolie [31]3 years ago
6 0

Answer:

1. 0.064

2. 1

3. 1

4. 9^2 or 3^4

Step-by-step explanation:

1. 0.4^3 means to do 0.4 times itself 3 times

2 and 3. Anything to the power of 0 equals 1

4. 9x9 - 9^2

3x3x3x3 - 3^4

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Determine the domain of the function graphed above.
Genrish500 [490]

Answer:

Domain: (-∞, ∞)

General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)

Step-by-step explanation:

According the the graph, we see that our x-values are spanning forever in both directions. Therefore our domain is:

(-∞, ∞) or -∞ < x < ∞

3 0
3 years ago
What is x equal to in this question​
marusya05 [52]

Answer:

x = 9

The drawings will help

8 0
3 years ago
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Jenny works at a video store.she earns $6.25 an hour plus $6 for each membership she sells. what is a formula?
mart [117]
A=(6.25h)+(6b)
total = hrs worked times hourly pay + number of memberships sold times what she gets from it
7 0
4 years ago
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Un triángulo rectángulo tiene un área de 84 pies2 y una hipotenusa de 25 pies de largo. ¿Cuáles son las longitudes de sus otros
jolli1 [7]

Answer:

7 feet and 24 feet

Step-by-step explanation:

In the right triangle, the hypotenuse is 25 feet long. The area of this triangle is 84 square feet.

Let x feet and y feet be the lengths of triangle's legs.

By the Pythagorean theorem,

x^2+y^2=25^2\\ \\x^2+y^2=625

The area of the right triangle is half the product of its legs, thus

84=\dfrac{1}{2}xy\\ \\xy=168

Solve the system of two equations:

\left\{\begin{array}{l}x^2+y^2=625\\ \\xy=168\end{array}\right.

From the second equation:

x=\dfrac{168}{y}

Substitute it into the first equation:

\left(\dfrac{168}{y}\right)^2+y^2=625\\ \\168^2+y^4=625y^2\\ \\y^4-625y^2+168^2=0\\ \\D=(-625)^2-4\cdot 168^2=(625-2\cdot 168)(625+2\cdot 168)=289\cdot 961=17^2\cdot 31\\ \\\sqrt{D}=17\cdot 31=527\\ \\y^2_{1,2}=\dfrac{-(-625)\pm 527}{2}=49,\ 576\\ \\y_1=7,\ y_2=-7,\ y_3=24,\ y_4=-24

The length of the leg cannot be negative, so

y_1=7\Rightarrow x_1=\dfrac{168}{7}=24\\ \\y_2=24\Rightarrow x_2=\dfrac{168}{24}=7

6 0
3 years ago
You take a bite out of a
Luda [366]
To solve this problem you must follow the proccedure below:

 a<span>. Find the perimeter and area of the cracker remaining: 

 The perimeter of  a quarter circle is:

 P=(</span>πr/2)+2r
 P=(πx3 cm/2)+2(3 cm)
 P=10.71 cm

 The perimeter of <span>the cracker remaining is:
</span><span>
 Pt=3 cm+6 cm+3 cm+10.71 cm
 Pt=22.71 cm

 The area of a quarter circle is:

 A=</span>πr²/4
 A=π(3 cm)²/4
 A=7.06 cm²
<span>
 The area of</span><span>of the cracker remaining is:
</span><span>
 At=Area of a square-Area of quarter circle
 At=L</span>²-(πr²/4)
 At=(6 cm)²-(π(3 cm)²/4)
 At=28.93 cm²
<span>
 b. About how many bites can you get from the entire cracker?</span> 

 Number of bites=L²/(π(3 cm)²/4)
 Number of bites=5
8 0
3 years ago
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