<u>9x</u> = <u>3y + 5</u>
9 9
x = 1/3y + 5/9
x - 5/9 = 1/3y + 5/9 - 5/9
x - 5/9 = 1/3y
3(x - 5/9) = 1/3y · 3
3x - 1 2/3 = y
y = 3x - 1 2/3
Answer:

Step-by-step explanation:
GIVEN: two two-letter passwords can be formed from the letters A, B, C, D, E, F, G and H.
TO FIND: How many different two two-letter passwords can be formed if no repetition of letters is allowed.
SOLUTION:
Total number of different letters 
for two two-letter passwords
different are required.
Number of ways of selecting
different letters from
letters


Hence there are
different two-letter passwords can be formed using
letters.
Answer:
The assertion that g(f(x)) is continuous at c is true.
Step-by-step explanation:

is continuous at c

is continuous at 
which is defined as per given data thus g(f(x)) is continuous at x=c
Answer:
the answer is 7
Step-by-step explanation:
7 is always right
Answer:
A) x, y turns into -x, -y
B) x, y turns into -y, x