You need to write an essay that has at least 500 words. You have written 285 words so far. Write and solve an inequality that re
1 answer:
Answer:
The minimum number of words left to write is 215
Step-by-step explanation:
Let
w -----> the number of words left to write
we know that
The number of words left to write plus the words written so far must be greater than or equal to 500 words
Remember that the word "at least" means "greater than or equal to"
Solve for w
Subtract 285 both sides
The minimum number of words left to write is 215
You might be interested in
Answer:
Step-by-step explanation:
Given
Required
Determine the domain
First, we need to solve for p
Substitute 70 for t in
Collect Like Terms
Solve for p
This implies that Larry can not invite up to 6 people.
Hence, the domain can be represented as:
Answer:
(a)There are 500 integers from 1 through 1,000 are multiples of 2.
There are 111 integers from 1 through 1,000 are multiples of 9.
(b)0.611
Step-by-step explanation:
Given the set of Integers from 1 through 1000
The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.
To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,
where first term, a =2, common difference, d =2
Nth term of an A.P,
- There are 500 integers from 1 through 1,000 are multiples of 2.
Similarly,
Given the set of Integers from 1 through 1000
The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.
To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,
where first term, a =9, common difference, d =9
Nth term of an A.P,
- There are 111 integers from 1 through 1,000 are multiples of 9.
(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.
There are a total of 1000 numbers between from 1 through 1,000
n(S)=1000
n(Multiples of 2)=500
n(Multiples of 9)=111
Therefore: