Answer:
$1.20
Step-by-step explanation:
Given that:
Price paid to buy 5 bags of chips = $6
To find:
Price per bag of chips in two digits after the decimal.
Solution:
To find the price of each bag of chips, we need to divide the price of 5 bags of chips with 5.
i.e. we need to divide $6 with 5, then we will get the price of each bag of chips.
Therefore, the answer is:
Price of each bag of chips is <em>$1.2.</em>
Answer:
1 / 5
Step-by-step explanation:
Given that:
Number of white marbles = 5
Number of blue marbles = 3
Number of green marbles = 7
Required is the approximate probability of drawing 2 green marbles, Note that drawing is done without replacement :
Probability = required outcome / Total possible outcomes
Total possible outcomes = sum of all marbles = (5 + 3 + 7) = 15 marbles
First draw:
P(Green) = 7 / 15
Second draw:
Required outcome = 7 - 1 = 6
Possible outcomes = 15 - 1 = 14
P(green) = 6 / 14
Probability of drawing out two green marbles :
(7/15 * 6/14) = 42 / 210 = 1 / 5
Answer:
Step-by-step explanation:
Yes, it's reasonable.
What you are doing is solving the question by rounding. You come up with an answer. Suppose you loose the decimal somewhere and you get 0.36? Is that reasonable? Do you just write the answer in the provided blank and move on. What now?
You get it wrong?!!
But your estimate should be about 9/3 = 3. Now you look at your calculator with great misgivings, because it made a mistake. Did it or did you? Well ultimately you did, but you have to blame something. So the calculator takes the heat.
Who knows? Maybe the decimal doesn't work. It's stuck or something. In any event you should be aware that there's no way the answer could be 0.36 when you estimate it to be 3.
Answer:
<em>(D). x = 2 , y = - 5</em>
Step-by-step explanation:
A = - 8 + 48 = 40
= -76 + 156 = 80
= 104 - 304 = - 200
<em>x =</em> 
= <em>2</em>
<em>y =</em> 
= <em>- 5</em>
<u><em>( 2, - 5 )</em></u>
The answer is 90
to find the median of a number is to just find the middle number if you were to put them in order from least to highest
also, there are mean, median, mode calculators that u can use online
